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Kazeer [188]
3 years ago
9

The line passing through point (2, 4), parallel to the line whose equation is y = x

Mathematics
1 answer:
grandymaker [24]3 years ago
7 0

Answer:

y = x + 2

Step-by-step explanation:

slope = 1

y = mx + b

4 = 1(2) + b

2 = b

y = x + 2

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In the circle below, suppose m VUX = 152° and mZUVW = 77º. Find the following.
bezimeni [28]

Given:

In the circle, m(\overarc{VUX})=152^\circ and m(\angle MUV)=77^\circ.

To find:

The following measures:

(a) m\angle VUX

(b) m\angle UXW

Solution:

According to the central angle theorem, the central angle is always twice of the subtended angle intercepted on the same same arc.

m(VUX)=2\times m\angle VWX

152^\circ=2\times m\angle VWX

\dfrac{152^\circ}{2}=m\angle VWX

76^\circ=m\angle VWX

In a cyclic quadrilateral, the opposite angles are supplementary angles.

UVWX is a cyclic quadrilateral. So,

m\angle VUX+m\angle VWX=180^\circ          [Opposite angles of a cyclic quadrilateral]

m\angle VUX+76^\circ=180^\circ

m\angle VUX=180^\circ-76^\circ

m\angle VUX=104^\circ

Now,

m\angle UXW+m\angle UVW=180^\circ          [Opposite angles of a cyclic quadrilateral]

m\angle UXW+77^\circ =180^\circ

m\angle UXW=180^\circ-77^\circ

m\angle UXW=103^\circ

Therefore, m\angle VUX=104^\circ  and m\angle UXW=103^\circ .

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monitta

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Answer:

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Step-by-step explanation:

The range is along y- axis and the domain is along x- axis.

Range is given in heights and domain is given in time seconds.

It can depicted that for t= 0 secs the ball is at 5 feet and so on .

Therefore the range is given by numbers from 5 to 12.5.

Whereas the domain is given by numbers 0 t0 8.5 seconds

3 0
2 years ago
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