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Papessa [141]
3 years ago
12

Can someone explain how to solve and graph this step-by-step?​

Mathematics
1 answer:
Maslowich3 years ago
7 0
(x,y)=(2,1) where the two lines intercept
so for the first equation you go on the y line and dot -4 then count up 5 times then right 2 times since it’s rise over run
for the second line start at positive 3 on the y line then it’s -1/1 which is up once and left once cause of the negative
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During the soccer season, Brielle scored 7 more goals than Olivia. Together they scored 39 goals.
Dmitry_Shevchenko [17]

Answer:

32.

Step-by-step explanation:

39 - 7 = 32

32 + 7 = 39

Brielle scored 32 points.

I hope this helped! :) Have a nice day.

6 0
3 years ago
. State the Fundamental Theorem of Arithmetic. Can two numbers have 18 as their HCF and 378
nadya68 [22]
I don’t now good luck!!!!!!!!!!!!!!!!
8 0
3 years ago
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The distribution of SAT II Math scores is approximately normal with mean 660 and standard deviation 90. The probability that 100
gayaneshka [121]

Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is of 660, hence \mu = 660.
  • The standard deviation is of 90, hence \sigma = 90.
  • A sample of 100 is taken, hence n = 100, s = \frac{90}{\sqrt{100}} = 9.

The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{670 - 660}{9}

Z = 1.11

Z = 1.11 has a p-value of 0.8665.

1 - 0.8665 = 0.1335.

0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213

7 0
2 years ago
If f(x)= 2x2-4x and g(x)=5-2x evalute f(x)-g(x) for x=5
dezoksy [38]
<span>f(x)= 2x²-4x
</span><span>g(x)= 5-2x

</span> f(x)-g(x) = 2x²-4x - ( 5-2x) = 2x² - 4x-5+2x= 2x² -2x-5
f(x)-g(x) = 2x² -2x-5
f(5)-g(5) = 2*5² -2*5-5=50-10-5 =35
f(5)-g(5) = 35
7 0
3 years ago
From 3 hours to 30 minutes Percentage
omeli [17]
What are u asking ? 30 minutes of 3 hrs the fraction would be 2/6 simplified would be 1/3 and the percentage would be 33.3 repeating percent
7 0
3 years ago
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