Answer:
32.
Step-by-step explanation:
39 - 7 = 32
32 + 7 = 39
Brielle scored 32 points.
I hope this helped! :) Have a nice day.
I don’t now good luck!!!!!!!!!!!!!!!!
Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
<h3>Normal Probability Distribution</h3>
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:

- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem:
- The mean is of 660, hence
.
- The standard deviation is of 90, hence
.
- A sample of 100 is taken, hence
.
The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

By the Central Limit Theorem



has a p-value of 0.8665.
1 - 0.8665 = 0.1335.
0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213
<span>f(x)= 2x²-4x
</span><span>g(x)= 5-2x
</span> f(x)-g(x) = 2x²-4x - ( 5-2x) = 2x² - 4x-5+2x= 2x² -2x-5
f(x)-g(x) = 2x² -2x-5
f(5)-g(5) = 2*5² -2*5-5=50-10-5 =35
f(5)-g(5) = 35
What are u asking ? 30 minutes of 3 hrs the fraction would be 2/6 simplified would be 1/3 and the percentage would be 33.3 repeating percent