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cupoosta [38]
3 years ago
7

A pole that is 2.8 mm tall casts a shadow that is 1.37 m long. At the same time, a nearby building casts a shadow that is 36.25

m long. how tall is the building? round your answer to the nearest meter.
​
Mathematics
2 answers:
Svetlanka [38]3 years ago
7 0
Answer is 74 meters
ZanzabumX [31]3 years ago
5 0

Answer:

this is the correct answer

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Use triangles to find the sum of the interior angle measures of the polygon.
Irina18 [472]

Answer:

360 degrees

Step-by-step explanation:

2 90 degress triangles 180= 1 triangle 360=2 triangles since there is 2 we can conclude that it is 360 degrees

6 0
2 years ago
Tay–Sachs Disease Tay–Sachs disease is a genetic disorder that is usually fatal in young children. If both parents are carri
BARSIC [14]

Answer:

a) 0.0156 = 1.56% probability that all children will develop the disease.

b) 0.4219 = 42.19% probability that only one child will develop the disease.

c) 0.1406 = 14.06% probability that the third children will develop the disease, given that the first two did not.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they carry the disease, or they do not. The probability of a children carrying the disease is independent of any other children, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that their offspring will develop the disease is approximately .25.

This means that p = 0.25

Three children:

This means that n = 3

Question a:

This is P(X = 3). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.25)^{3}.(0.75)^{0} = 0.0156

0.0156 = 1.56% probability that all children will develop the disease.

Question b:

This is P(X = 1). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{3,1}.(0.25)^{1}.(0.75)^{2} = 0.4219

0.4219 = 42.19% probability that only one child will develop the disease.

c. The third child will develop Tay–Sachs disease, given that the first two did not.

Third independent of the first two, so just multiply the probabilities.

First two do not develop, each with 0.75 probability.

Third develops, which 0.25 probability. So

p = 0.75*0.75*0.25 = 0.1406

0.1406 = 14.06% probability that the third children will develop the disease, given that the first two did not.

6 0
3 years ago
Can somone explain to me how to do this and help me thansk!!!
Gnesinka [82]
=> x² = (2.4)² + (4.8)²

=> x² = 5.76 + 23.04

=> x² = 28.8

=> x = 5.366563146

=> x = 5.4

Ans: 2nd option (5.4)

Hope this helps!
6 0
3 years ago
Which answer describes the transformation of f(x)=x2−1 to g(x)=(x−1)2−1 ?
artcher [175]
A vertical translation 1 unit down since for example x is 1, if u plug it in both equations it is f(1)=1*2-1 which equals f(1)=1 and the point is (1,1) for the other one, g(1)=(1-1)2-1 it equals g(1)=-1
4 0
3 years ago
Read 2 more answers
Can someone please answer this fast, ty
yuradex [85]

Answer:

13p

Step-by-step explanation:

12p+p

Factor out the p

p(12+1)

p (13)

13p

3 0
3 years ago
Read 2 more answers
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