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ddd [48]
2 years ago
11

Which of the following is an example of an open equation? 5x + 7 = 12 , 12 + (-8) = 4 , 25 = 5 (5) , 8 + 0 =8

Mathematics
1 answer:
spayn [35]2 years ago
7 0

An open equation is an equation that contain one or more unknow variables.

And that/those variable(s) can be found by solving the equation that make the equation true.

A variable is an English alphabet.

For example, a,b, x, y,z etc.

A variable represents a unknow value for a particular quantity.

In the given options 5x + 7 = 12 , 12 + (-8) = 4 , 25 = 5 (5) , 8 + 0 =8 .

In first option, we have unknow variable x is there.

But in all other options we don't value any variable.

Therefore, all other options can't be open equation.

So, final answer is 5x + 7 = 12 is the only open equation in given options.

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Given r(x) = x square +2x -1 and s(x) = x-1 what is the value of r(s(3))
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Answer:

r(s(3))=7

Step-by-step explanation:

we have

r(x)=x^{2} +2x-1

s(x)=x-1

we know that

The function composition is equal to

(r ∘ s )(x) = r(s(x))

In the function r(x) substitute the variable x by the function s(x)

so

r(s(x))=(x-1)^{2} +2(x-1)-1

For x=3

substitute the value of x=3 in the function composition

r(s(3))=(3-1)^{2} +2(3-1)-1

r(s(3))=(2)^{2} +2(2)-1

r(s(3))=4+4-1

r(s(3))=7

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\frac{dy}{dx} = 2 - 0 - \frac{2\sqrt3}{\sqrt x}\\\\\frac{dy}{dx} = 2 -  \frac{2\sqrt3}{\sqrt x}\\

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Step-by-step explanation:

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Pls help I’ll give brainliest
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