Ask question

Ask question

All categories

3 years ago

11

Which of the following is an example of an open equation? 5x + 7 = 12 , 12 + (-8) = 4 , 25 = 5 (5) , 8 + 0 =8

1 answer:

spayn [35]3 years ago

7 0

An open equation is an equation that contain one or more unknow variables.

And that/those variable(s) can be found by solving the equation that make the equation true.

A variable is an English alphabet.

For example, a,b, x, y,z etc.

A variable represents a unknow value for a particular quantity.

In the given options 5x + 7 = 12 , 12 + (-8) = 4 , 25 = 5 (5) , 8 + 0 =8 .

In first option, we have unknow variable x is there.

But in all other options we don't value any variable.

Therefore, all other options can't be open equation.

So, final answer is 5x + 7 = 12 is the only open equation in given options.

You might be interested in

27? i cant figure out her mistake can anyone help ?

expeople1 [14]

The mess up occurs in one of the first things she says. She first claims that 7^2 +25^2 = 24^2
Wait a minute... slow your roll there.
25 is the hypotenuse, or the longest side of the triangle AND opposite the right angle (but we aren't supposed to know that yet).
The Pythagorean Theorem holds that a^2 + b^2 = c^2, where a & b are the legs of the triangle & c is the hypotenuse. So, she got the formatting correctly, but she switched 24 & 25.
Hope this helps!

4 0

3 years ago

Read 2 more answers

The area of circle is 64 square meters.What is the radius?

Mrac [35]

Answer:

radius=8

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

(-5,3);5×=4y+9 can you help me solve

kompoz [17]

Answer:

-25 ≠ 21

Step-by-step explanation:

it looks like the question is asking you to solve 5x=4y+9 when given the ordered pair (-5,3)

you would substitute -5 for x and 3 for y in the equation

5(-5) = 4(3) + 9

-25 = 12 + 9

-25 = 21

the question is asking you to see if the left side is equal to the right side of the equation

-25 is not equal to 21, therefore (-5,3) is not a solution to the equation

4 0

3 years ago

Solve for x in the diagram.

BARSIC [14]

Answer:

x = 20

Step-by-step explanation:

x° + 2x° + (x+10)° = 90°

3x° + x° + 10° = 90°

4x° + 10° = 90°

4x° = 90°-10°

4x° = 80°

x = 80/4

x = 20

8 0

3 years ago

Read 2 more answers

Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s

Nataliya [291]

Answer:

$f(x)=\frac{1}{2}x^2-4x+5$

Step-by-step explanation:

A parabola is written in the form

$f(x)=a((x-h)^2+k)$ (1)

where:

$h$ is the x-coordinate of the vertex of the parabola

$ak$ is the y-coordinate of the vertex of the parabola

$a$ is a scale factor

For the parabola in the problem, we know that the vertex has coordinates (4,-3), so we have:

$h=4$ (2)

$ak=-3$

From this last equation, we get that $a=\frac{-3}{k}$ (3)

Substituting (2) and (3) into (1) we get the new expression:

$f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3$ (4)

We also know that the parabola contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

$-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6$

So we also get:

$a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}$

So the equation of the parabola is:

$f(x)=\frac{1}{2}((x-4)^2 -6)$ (5)

Now we want to rewrite it in the standard form, i.e. in the form

$f(x)=ax^2+bx+c$

To do that, we simply rewrite (5) expliciting the various terms, we find:

$f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5$

6 0

3 years ago