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nata0808 [166]
3 years ago
11

2. Evaluate the expression: -32-4-59) - (15 - 33). O A. 16 O B. 34 O C. 52 O D-2

Advanced Placement (AP)
1 answer:
zlopas [31]3 years ago
6 0
B.34 would be the answer to this question
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What is the arrangement of the outer planets? What effect does their placement have on the planets
Sergeu [11.5K]
The arrangements of the outer planets are in this sequence 1. Mercury 2. Venus 3. Earth 4. Mars 5. Jupiter 6. Saturn 7. Uranus.

Currently, there's no effect of their placement have on the other planets. But before they affected each other because of resonance which contributes to the movement of each planet.

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HELP ASAP <br> What characteristics are typical of personality disorders?
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Answer:

Image result for What characteristics are typical of personality disorders?

Diagnosis of a personality disorder requires the following: A persistent, inflexible, pervasive pattern of maladaptive traits involving ≥ 2 of the following: cognition (ways or perceiving and interpreting self, others, and events), affectivity, interpersonal functioning, and impulse control.

Explanation:

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3 years ago
HEYY I NEED HELP WITH AN AP CALC ASSIGNMENT ASAP
Vladimir79 [104]

CALCULATOR PART

1. The area of R + S is unsigned, meaning you want to find

\displaystyle\int_a^b\left|f(x)-g(x)\right|\,\mathrm dx

where [a,b] is the interval between the leftmost and rightmost intersections of f and g.

First use your calculator to find these intersections:

\cos x=\dfrac{x+1}3\implies x\approx-3.64,x\approx-1.86,x\approx0.889

so that a=-3.64 and b=0.889. Now compute the integral using your calculator:

\displaystyle\int_a^b\left|f(x)-g(x)|\,\mathrm dx\approx1.662

2. The volume, using the washer method, is given by the integral

\displaystyle\pi\int_{-1.86}^{0.889}(|2-g(x)|^2-|2-f(x)|^2)\,\mathrm dx\approx12.078

3. A circle of radius r has area \pi r^2; a semicircle with the same radius thus has area \frac{\pi r^2}2. Each cross section of this solid is a semicircle whose diameter is the vertical distance between f(x) and g(x), or |f(x)-g(x)|. In terms of the diameter d=2r, the area of each semicircle would be \frac{\pi d^2}8. Then the volume of the solid is

\displaystyle\frac\pi8\int_{-3.64}^{-1.86}|f(x)-g(x)|^2\,\mathrm dx\approx0.0425

NON-CALCULATOR PART

4. The mean value theorem says that for a function F continuous on an interval [a,b] and differentiable on (a,b), there is some c\in(a,b) such that

F'(c)=\dfrac{F(b)-F(a)}{b-a}

If this F happens to be an antiderivative of f, then we end up with

f(c)=\displaystyle\frac1{b-a}\int_a^bf(x)\,\mathrm dx

\cos x is continuous and differentiable everywhere, so the MVT applies. We have F'(x)=f(x)=\cos x, so the MVT tells us there is some c\in[0,\pi such that

\cos c=\dfrac{\sin\pi-\sin0}{\pi-0}=0

That is, the average value of f(x) on [0,\pi] is 0. The MVT says there is some c in the interval such that the function takes on the average value itself; this happens for c=\frac\pi2.

5. This question seems to be incomplete...

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4 years ago
The female sex cells are the ____
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3 years ago
During ,the molecules in a solid gain large amounts of energy and leave the surface of the solid
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Answer:

it's metal

Explanation:

because it so rough

3 0
4 years ago
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