Answer:
The population of deer at any given time = 200(e^0.03t) ÷ (1.5 + (e^0.03t))
Step-by-step explanation:
This is an example of logistic equation on population growth
carrying capacity, k = 200
Rate, r = 3% = 0.03
Initial Population, P1 = 80
P(t) =?
P(t) = (P1 (k)(e^rt)) ÷ (k- P1 + P1(e^rt))
P(t) = (80 (200)(e^0.03t)) ÷ (200 - 80 + 80(e^0.03t))
= (16000(e^0.03t)) ÷ (120 + 80(e^0.03t))
= 200(e^0.03t) ÷ (1.5 + (e^0.03t))
Plug the values into point slope and simplify
y-4= 4(x-(-2))
y-4= 4x+8
y= 4x+12
Final answer: y=4x+12
(5,3) is the answer for the current question
We know that formula for circumference is 2πr
Since we have circumference of 2π, that would means 2π = 2πr.
We need to solve for r. We can divide both sides by 2π:
2π / 2π = 2πr / 2π
1 = r
So radius is 1.
Now the formula for area of circle is πr². So plug in r=1 and that would be
π(1)²
π
So area of circle is π.
Hope this helps.
P-1 = 5p+8p-8
p-1 = 13p-8 (collect like terms)
p+7 = 13p (add 8 to both sides)
7 = 12p (minus p from both sides)
7/12 = p (divide both sides by 12)
p = 7/12
