Solving the following inequation:
(x - 8) (x + 1) > 0
We are going to find the sign both parts of the multiplication,
(x - 8) and (x + 1), have when
x < - 8
-8 < x < 1
1 < x
Then we know (x - 8) (x + 1) > 0 whenever (x - 8) (x + 1) is positive
We can see in the figure (x - 8) (x + 1) is positive when x < -8 and x > 1
Then
Answer:B
Answer:
Step-by-step explanation:
Given
Required
Determine which coordinate fall in the right quadrant
First, we split the each quadrant into x and y axis
In the first:
x and y is +
In the second:
x is - and y is +
In the third
x and y are -
In the fourth
x is + and y is -
Comparing the given coordinates to their respective quadrants, base on the conditions stated above
is correct
is correct
is correct
is correct
is incorrect