Which of the following equation does best represent the graph below?

The Bureau of Labor Statistics reported that the average yearly income of dentists in the year 2005 was $110,000. A sample of 81

Sholpan [36]

Answer:

a) We want to test to determine if there has been a significant increase in the average yearly income of dentists, the system of hypothesis would be:

Null hypothesis: $\mu \leq 110000$

Alternative hypothesis: $\mu > 110000$

b) $z=\frac{120000-110000}{\frac{36000}{\sqrt{81}}}=2.5$

c) $p_v =P(Z>2.5)=0.0062$

We see that the p value is lower than the significance level of $1-0.95=0.05$ so then we can conclude that the true mean is significantly higher than 110000 because we reject the null hypothesis.

Step-by-step explanation:

Information given

$\bar X=12000$ represent the sample mean for the yearly income in 2006 for the dentists

$\sigma= 36000$ represent the sample population deviation

$n=81$ sample size

$\mu_o =110000$ represent the value that we want to test

$\alpha=0.05$ represent the significance level

z would represent the statistic

$p_v$ represent the p value for the test

a) Hypothesis to verify

We want to test to determine if there has been a significant increase in the average yearly income of dentists, the system of hypothesis would be:

Null hypothesis: $\mu \leq 110000$

Alternative hypothesis: $\mu > 110000$

Since we know the population deviation the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

b) Statistic

When we replace the data given we got:

$z=\frac{120000-110000}{\frac{36000}{\sqrt{81}}}=2.5$

c) P value

Now we can find the p value using the fact that we are conducting a right tailed test:

$p_v =P(Z>2.5)=0.0062$

We see that the p value is lower than the significance level of $1-0.95=0.05$ so then we can conclude that the true mean is significantly higher than 110000 because we reject the null hypothesis.

7 0

4 years ago

Pls solve and show the steps, I'll give brainliest to whoever replies first and accurately

AleksandrR [38]

3(x-1) = 2x - y

3x-3 = 2x-y

3x-2x+y = 3

x + y = 3 ----> (1)

2(x+y) = 3+3y

2x + 2y = 3 + 3y

2x + 2y - 3y = 3

2x - y = 3 -----> (2)

make equation (1) and (2) together

x + y + 2x - y = 3+3

3x = 6

x = 2

now make x = 2 in equation (1)

x + y = 3

2 + y = 3

y = 3-2

y = 1

(x,y) = (2,1)

6 0

3 years ago

A rectangular football field is 64 meters wide and 100 meters long. A player runs from one corner of the firmed in a diagonal li

Lynna [10]

Answer:

The player ran approximately 119119119 meters

Step-by-step explanation:

We can use the Pythagorean Theorem to find the length of the diagonal line.

The equation for the Pythagorean Theorem is

a^2 + b^2 = c^2a

2

+b

2

=c

2

a, squared, plus, b, squared, equals, c, squared

where aaa and bbb are the lengths of the two legs of the triangle, and ccc is the length of the hypotenuse.

In this case a=64,b=100,a=64,b=100,a, equals, 64, comma, b, equals, 100, comma and c=xc=xc, equals, x.

Hint #33 / 4

\begin{aligned} 64^2+100^2 & =x^2\\ 4096+10000 & = x^2\\ 14096 & = x^2\\ \sqrt{14096} & = x\\ 118.726 & \approx x \end{aligned}

64

2

+100

2

4096+10000

14096

118.726

=x

2

=x

2

=x

2

=x

≈x

The player ran approximately 119119119 meters.

5 0

3 years ago

Read 2 more answers

Marjorie deposits $1275 into an account that makes 6.2% interest per year. How much interest will she make in a year?

KengaRu [80]

Is it simple or compound interest?

5 0

3 years ago

Can someone help me with this please?

muminat

(2/3)^(1-1) + (2/3)^(2-1) + (2/3)^(3-1) + (2/3)^(4-1)=
(2/3)^0 + (2/3)^1 + (2/3)^2 + (2/3)^3=
1 + (2/3) + (4/9) + (8/27) =
(27/27) + (18/27) + (12/27) + (8/27) =
65/27 = 2 11/27

6 0

3 years ago