Let x be the number of $10 bills in Iago pocket.
1. If he has twice as many $1 bills as $10 bills, then he has (2x) $1 bills.
2. He has two fewer $20 bills than he does $10 bills, then he has (x-2) $20 bills.
3. He has three more $5 bills than $10 bills, then he has (x+3) $5 bills.
In total he has $160 that is x·10+2x·1+(x-2)·20+(x+3)·5.
Equate these two expressions and solve the equation:

Thus, he has
- 5 bills for $10;
- 10 bills for $1;
- 3 bills for $20;
- 8 bills for $5.
Isolate the w
w/3 = 5
Note the equal sign. What you do to one side, you do to the other.
Multiply 3 to both sides
w/3(3) = 5(3)
w = 5(3)
Multiply
w = 15
15 is your answer for w
hope this helps
Answer:
C. The mean will increase and ty e median will remain the same.
Answer:
8/9
Step-by-step explanation:
8/9= 0.88888888889