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2 years ago

What is the improper fraction of 136/20

2 answers:

5 0

136 / 20 = (2 3 * 17) / (2 2 * 5) = ((2 3 * 17) : 2 2 ) / ((2 2 * 5) : 2 2 ) = (136 : 4) / (20 : 4) ... 34 > 5 =>improper fraction Rewrite: 34 : 5 = 6 and remainder = 4 => 34 / 5 ...

s344n2d4d5 [400]2 years ago

5 0

The improper fraction of 136/20 would be 34/5
136 / 20 =
(2^3 * 17) / (2^2 * 5) =
((2^3 * 17) : 2^2) / ((2^2 * 5) : 2^2) =
(136 : 4) / (20 : 4) = 34/5
Hope this helps you!!

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Step-by-step explanation:

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Arte-miy333 [17]

Answer:

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

The null hypothesis is accepted .

Assume the population variances are approximately the same

Step-by-step explanation:

Explanation:-

Given data a random sample of 20 turkeys sold at the chain's stores in Detroit yielded a sample mean of 17.53 pounds, with a sample standard deviation of 3.2 pounds

The first sample size 'n₁'= 20

mean of the first sample 'x₁⁻'= 17.53 pounds

standard deviation of first sample S₁ = 3.2 pounds

Given data a random sample of 24 turkeys sold at the chain's stores in Charlotte yielded a sample mean of 14.89 pounds, with a sample standard deviation of 2.7 pounds

The second sample size n₂ = 24

mean of the second sample "x₂⁻"= 14.89 pounds

standard deviation of second sample S₂ = 2.7 pounds

Null hypothesis:-H₀: The Population Variance are approximately same

Alternatively hypothesis: H₁:The Population Variance are approximately same

Level of significance ∝ =0.05

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Test statistic :-

$t = \frac{x^{-} _{1} - x_{2} }{\sqrt{S^2(\frac{1}{n_{1} } }+\frac{1}{n_{2} } }$

where $S^{2} = \frac{n_{1} S_{1} ^{2}+n_{2}S_{2} ^{2} }{n_{1} +n_{2} -2}$

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substitute values and we get S² = 40.988

$t= \frac{17.53-14.89 }{\sqrt{40.988(\frac{1}{20} }+\frac{1}{24} )}$

t = 1.3622

Calculated value t = 1.3622

Tabulated value 't' = 2.081

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

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