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Andreas93 [3]
2 years ago
7

What is the improper fraction of 136/20

Mathematics
2 answers:
Yakvenalex [24]2 years ago
5 0
136 / 20<span> = (2 3 * 17) / (2 2 * 5) = ((2 3 * 17) : 2 2 ) / ((2 2 * 5) : 2 2 ) = (136 : 4) / (20 : 4) ... 34 > 5 =></span>improper fraction<span> Rewrite: 34 : 5 = 6 and remainder = 4 => 34 / 5 ...</span>
s344n2d4d5 [400]2 years ago
5 0
The improper fraction of 136/20 would be 34/5
136 / 20 =
(2^3 * 17) / (2^2 * 5) =
((2^3 * 17) : 2^2) / ((2^2 * 5) : 2^2) =
(136 : 4) / (20 : 4) = 34/5
Hope this helps you!!
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Answer:

A

Step-by-step explanation:

Calculate the slope of the given points with the point (- 2,  5 )

If the slope is - \frac{3}{4} then the point is on the line

Calculate slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (6, - 1)

m = \frac{-1-5}{6+2} = \frac{-6}{8} = - \frac{3}{4} ← point (6, - 1) is on the line

Repeat with (x₁, y₁ ) = (- 2, 5 ) and (x₂, y₂ ) = (2, 8)

m = \frac{8-5}{2+2} = \frac{3}{4} ← point (2, 8) is not on the line

Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (- 5, 1)

m = \frac{1-5}{-5+2} = \frac{-4}{-3} = \frac{4}{3} ← point (- 5, 1) is not on the line

Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (1, 1)

m = \frac{1-5}{1+2} = - \frac{4}{3} ← point (1, 1) is not on the line

Thus the point on the line is (6, - 1 ) → A

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A. at (8,7) the maximum value is 98

Step-by-step explanation:

First draw the region, that is bounded by all

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Now you can see where the line f(x,y)=7x+6y

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Step-by-step explanation:

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