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3 years ago

Did the scale factor of 0.75 enlarge reduce or stay the same?

Mathematics

2 answers:

elixir [45]3 years ago

6 0

Answer:

$\huge\boxed{\sf Reduces}$

Step-by-step explanation:

Since the scale factor of 0.75 is less than 1, So the dilated image is a reduced image.

Thus the scale factor of 0.75 reduces the dilated image.

$\rule[225]{225}{2}$

Hope this helped!

<h3>~AnonymousHelper1807</h3>

nalin [4]3 years ago

6 0

Answer:

-it reduces-

Step-by-step explanation:

good luck:)

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Math help! plsss on these questions

likoan [24]

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3 years ago

I need to find surface area of a cylinder. Formula being used: S.A= L x W +

Arturiano [62]

Answer:

90π yd²

Step-by-step explanation:

the surface area of a cylinder is the sum of the lateral area and twice the aera of one end of the cylinder: π·d·l, where l represents the length of the cylinder. Here, the lateral surface area is π·6 yd·12 yd, or 72π yd².

The two ends add the following to the total surface area:

2·π·(d/2)², or 2π·d²/4.

Thus, the total surface area of the cyl. is

A = 2π·(6 yd)²/4 + 72π yd², or

A = 18π yd² + 72π yd² = 90π yd²

Note: Please check your source. L x W + 2pi ·r ^2 is incorrect.

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3 years ago

What is 17 1/3 x 8 and how much water will each group get

stealth61 [152]

Answer:

The Answer to 17 1/3 x 8 is 138.67

There is not enough context to answer the second question.

8 0

3 years ago

What is the value represented by the letter A on the box plot of the data?

Aloiza [94]

It would be b because if you take 10 and shusbejsjdhebe

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2 years ago

Brook makes this conjecture: Because the angles are equal, the proportion of area of each sector relative to the area of the giv

AnnZ [28]

Answer:

The Brooks conjecture is true as the proportion of the area of a sector to the area of a circle is only dependent on the angle.

Step-by-step explanation:

The area of a sector for a radius r and an angle θ is given as

$\Delta Sector=\dfrac{1}{2}r^2\theta$

Whereas the area of a circle for a radius r is given as

$\Delta Circle=\pi r^2$

Now the ratio is given as

$\dfrac{\Delta Sector}{\Delta Circle}=\dfrac{\dfrac{1}{2}r^2\theta}{\pi r^2}$

Here as r is the radius of the circle and it is the same therefore the above ratio is simplified to

$\dfrac{\Delta Sector}{\Delta Circle}=\dfrac{\theta}{2\pi }$

Here as π is constant the only variable here is θ. Thus according to Brooks conjecture when the angles are equal, the proportion of area of each sector relative to the area of the given circle is also equal is true.

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3 years ago