Answer:
Step-by-step explanation:
a). Given a parametric equation, we are describing a set of coordinates based on the value of t. The variable t is called the parameter.
b) we have the following equations. x=t y=t^2, so in order for us to know where the object is at t=t' we must replace t with the specific value t'. Hence, when t=0 the object is at (0,0^2) = (0,0) (the origin). When t=6, the object is at (6,6^2) = (6,36).
c). To eliminate the parameter, we replace the parameter in one equation by using the second equation. Recall that we have that x=t. Then, by replacing in the second equation, we have the following
where
False. A reflection over the y-axis would result in: (-8,5)
Answer:
the answer is a where x=8
Explanation:
cross multiplication method
Answer:
C abc dm<a=60> o+a ,m(b=60o'a is equal to 150
Answer:
6.07
Step-by-step explanation: