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PtichkaEL [24]
3 years ago
14

HELP ME GUYS I AM ILLITERATE find the size of unknown angle

Mathematics
2 answers:
Nadusha1986 [10]3 years ago
5 0

Answer:

Step-by-step explanation:

ΔAOC is an isosceles triangle as OC = OA ----> RADIUS

42 + 42 + ∠AOC = 180   {Angle sum property}

       84 + ∠AOC = 180

              ∠AOC = 180 - 84

∠AOC = 96°

y = 96/2    {Central angle theorem}

y = 48° ------------(I)

∠B + ∠D = 180    {sum of opposite angles of Cyclic  Quadrilateral}

x + y = 180

x + 48 =  180        {from (I) }

x = 180 - 48

x =  132°

Vlada [557]3 years ago
3 0

Answer:

x =  132°

Step-by-step explanation:

ΔAOC is an isosceles triangle as OC = OA ----> RADIUS

42 + 42 + ∠AOC = 180   {Angle sum property}

      84 + ∠AOC = 180

             ∠AOC = 180 - 84

∠AOC = 96°

y = 96/2    {Central angle theorem}

y = 48° ------------(I)

∠B + ∠D = 180    {sum of opposite angles of Cyclic  Quadrilateral}

x + y = 180

x + 48 =  180        {from (I) }

x = 180 - 48

x =  132°

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I need some serious help rn, i got stuck
nordsb [41]

Answer:

I think it is add 11 both sides? If it is wrong i am sooooo sorry

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
use the line graph to answer the question 9 and 10 how much did the temperature change from Sunday High to Mondays High ? what w
Marizza181 [45]

Answers:

<em>How much did the temperature change from Sunday High to Mondays High?</em>

Change = 4 °C

<em>What was the difference between the high temperatures on Friday and Wednesday?​</em>

Difference = 10 °C

Explanation:

Taking into account the graph, we get that the high temperature each day is:

Sunday: -10°C

Monday: -6 °C

Tuesday: - 4 °C

Wednesday: -6 °C

Thursday: 0 °C

Friday: 4 °C

Saturday: -2 °C

So, the change from Sunday High to Mondays High can be calculated as:

Change = Monday - Sunday

Change = -6 °C - (- 10 °C)

Change = -6 °C + 10 °C

Change = 4 °C

In the same way, the difference between the high temperatures on Friday and Wednesday can be calculated as:

Difference = Friday - Wednesday

Difference = 4 °C - (-6 °C)

Difference = 4 °C + 6 °C

Difference = 10 °C

Therefore, the answers are:

<em>How much did the temperature change from Sunday High to Mondays High?</em>

Change = 4 °C

<em>What was the difference between the high temperatures on Friday and Wednesday?​</em>

Difference = 10 °C

6 0
1 year ago
What is the value of x?
V125BC [204]
The value of X is 1
7 0
3 years ago
A line is tangent to the circle x^2+y^2=41, at the point (-4,-5)
VashaNatasha [74]
If the equation of the circle is x^2+ y^2 = 41, we must first understand the parts of the equation.
 A general circle's equation is (x-h)^2+(y-k)^2= r^2  
(h.k) is the radius of the circle
r is the radius of the circle
Another useful fact to know is that tangent lines touch the circle at one point (4,5)

Since in our original equation there are no h or k values, we can assume that the center of the circle is (0,0). 

The formula for slope is <u>Y1-Y2</u>
                                   X1-X2
We can break this down with our two points (center and tangent)
  (0,0)    and   (-4,-5)
(X1,Y1) and (X2,Y2)

therefore, we will put the equation as such
<u>0-(-5)= 5</u>  = <em> </em><u><em>5</em></u>
0-(-4)= 4     <em> 4</em>

<em>this is our slope from the center to the point of tangency.</em>

We know that tangent lines are perpendicular to the radius, which we've already found the slope of. Perpendicular lines are opposite reciprocals of the line they are perpendicular to. 

Therefore, we take our slope from center to the tangent, and make it opposite and then take the reciprocal of that slope, which will give us the slope of the tangent line itself. (note: reciprocal means flip the numerator and denominator)
<u>5</u> =  <u>-5</u>  =  <u>-4</u><u>
</u>4     4        5   

Now, we have a point on the line, and the line's slope. We can use slope-intercept equation to find the equation of the line.

Slope-int      y=mx+b
(x,y) is a point,
m is the slope
b is the y intercept  ( the point where x=0, or where its on the y axis)

now we plug things in
(-4,-5) is our point,
<u>-4</u>  is our slope
5

-5=<u>-4</u>(-4)+b       After we plug things in, solve for b
     5

-5= 3.2+b

-1.8= b  or  b=  <u />1 <u>4</u>
                         5

Now we just need to rewrite our equation with all our components.
(-4.-5) = point
<u>-4</u>  = slope<u>
</u>5
1 <u>4</u> = y-intercept<u>
</u>   5

<em>y=</em><u><em>-4</em></u><em> x+ 1 </em><u><em>4</em></u><em>     This is the equation of the tangent line</em><u>
</u><em>    5         5</em>


Hope that helped
7 0
3 years ago
Solve the equation for the indicated variable (for c)<br><img src="https://tex.z-dn.net/?f=15%20%3D%20%20-%203%282c%20%2B%20d%29
11Alexandr11 [23.1K]

Answer:

c= -2.5-0.5d

Step-by-step explanation:

15=-3(2c+d)

15=-6c+-3d

15+3d=-6c

-2.5-0.5d=c

5 0
3 years ago
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