What is the experimental probability of NOT landing on green<br><br> 22%<br> 25%<br> 75%<br> 78%

5000 at 12% compound quarterly compared interest earned after 5 year's

hichkok12 [17]

Answer:

A = P(1+r÷100)^n

where A is amount after some days

r is the rate

n is the number of years

p is the principle (the amount of money before the interest)

A = 5000 ( 1 + 12÷100)^5

A = 8811.70

A = 8812

8 0

3 years ago

ROUND 977.259856871 TO 3 DECIMAL PLACES HELP!

sasho [114]

3 decimal places would be where the 9 is, since the next number is 8 , the 9 would become a 0 and the number before it (5) would become a 6

so it would be 977.260

6 0

2 years ago

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The table shows the numbers y of students absent from school x days after a flu outbreak.

allsm [11]

A function that models the data is given by this quadratic equation, y = -0.4908x² + 5.8845x + 1.3572.
The number of students that are absent 10 days after the outbreak is equal to 11 students.

<h3>What is a scatter plot?</h3>

A scatter plot can be defined as a type of graph which is used for the graphical representation of the values of two (2) variables, with the resulting points showing any association (correlation) between the data set.

<h3>What is a quadratic function?</h3>

A quadratic function can be defined as a mathematical expression (equation) that can be used to define and represent the relationship that exists between two or more variable on a graph.

In Mathematics, the standard form of a quadratic equation is given by;

ax² + bx + c = 0

By critically observing the graph (see attachment) which models the data in the given table, we can infer and logically deduce that the quadratic function is given by:

y = -0.4908x² + 5.8845x + 1.3572

For the number of students that are absent 10 days after the outbreak, we have:

y = -0.4908(10)² + 5.8845(10) + 1.3572

y = -0.4908(100) + 58.845 + 1.3572

y = -49.08 + 58.845 + 1.3572

Number of students, y = 11.12 ≈ 11 students.

Read more on scatterplot here: brainly.com/question/6592115

#SPJ1

5 0

1 year ago

As part of their fundraising for Right To Play, the student council is having a fun-fair at lunch in the school yard. You will b

Lubov Fominskaja [6]

Step-by-step explanation:

I used a co-ordinate graph and place the ticket booth at the origin then I chose difference of four but you can choose any and place three events equidistant from the origin by using the X- and Y- axis to easily determined a distance of 4 from the origin .

(0-4, 0) =( 4,0)

(0+4, 0) = (4 ,0)

(0, 0+4) = (0, 4)

if the both are placed first u would need to find the equation of a circle that contains all three points and place the booth at centre

you do this by creating the system of 3 equations inputting the x,y coordinates of each booth and solving for h,k,r

equation of a circle (X-H) 2 +( Y-K) 2 = r2

Hope It helps

:DD have a nice day

6 0

3 years ago

What is the perimeter of the figure in the diagram (round to three decimal places if necessary)?

Y_Kistochka [10]

Perimeter (p) = length around a shape.
So any horizontal sides we can add based upon their length in x-values and any vertical sides we can add based upon their length in y-values. The diagonal sides we can find by the distance formula:
$d = \sqrt{( {(x2 - x1)}^{2} + {(y2 - y1)}^{2} }$
So the bottom base goes from x=1 to x=8, then up 1, right 1, and up from y=3 to y=9, then left from x=9 to x=6, down from y=9 to y=6, left from x=6 to x=3.
So far that is: (8-1)+1+1+(9-3)+(9-6)+(9-6)+(6-3)
= 7+2+6+3+3+3 = 24
Now for the diagonal:
$d = \sqrt{( {(x2 - x1)}^{2} + {(y2 - y1)}^{2}) } \\ = \sqrt{( {(3- 1)}^{2} + {(6 - 2)}^{2} )} \\ = \sqrt{( {2}^{2} + {4}^{2} )} = \sqrt{(4 + 16)} \\ = \sqrt{20} = 2 \sqrt{5} = 4.47$
P = 24 + 4.47 = 28.47
D) 28.472

4 0

3 years ago

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What is the experimental probability of NOT landing on green 22% 25% 75% 78%