2 + 3w < -1 < 3w + 5 |subtract 3w from all sides
2 < -1 - 3w < 5 |add 1 to all sides
3 < -3w < 6 |change the signs
-3 > 3w > -6 |divide both sides by 3
-1 > w > -2 → -2 < w < -1 → w ∈ (-2, -1)
C would be your answer because inverse variation is y=k/x
Answer:
n = 6
Step-by-step explanation:
6÷4 = 9÷n
6n = 9*4
6n = 36
n = 6
Answer:

Step-by-step explanation:
Given that,
In an AP, the 6th term is 39 i.e.

In the same AP, the 19th term is 7.8 i.e.

Subtract equation (1) from (2).
7.8 - 39 = a+18d - (a+5d)
-31.2 = a +18d-a-5d
-31.2 = 13d
d = -2.4
Put the value of d in equation (!).
39 = a+5(-2.4)
39 = a- 12
a = 39+12
a = 51
The sum of n terms of an AP is given by :
![S_n=\dfrac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cdfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Put n = 25 and respected values,
![S_{25}=\dfrac{25}{2}[2(51)+24(-2.4)]\\\\=555](https://tex.z-dn.net/?f=S_%7B25%7D%3D%5Cdfrac%7B25%7D%7B2%7D%5B2%2851%29%2B24%28-2.4%29%5D%5C%5C%5C%5C%3D555)
Hence, the sum of first 25 terms of the AP is equal to 555.
Answer:
0.88
Step-by-step explanation:
Given:
A spinner is divided into 4 sections using the colours: red, orange, yellow, and green. After 50 trials, the spinner landed on red 10 times, on orange 16 times, on yellow 6 times, and on green 18 times.
To find: probability of the spinner not landing on yellow
Solution:
Probability is the chance of occurrence of some event.
Total number of outcomes = 50
Number of favourable outcomes = 50 - 6 = 44
Probability of the spinner not landing on yellow = Number of favourable outcomes / Total number of outcomes = 