V=(4/3)pir^3
find smaller
V=(4/3)pi8^3
V=(4/3)pi512
V=(2048/3)pi
twice of that
Vbig=2*(2048/3)pi
Vbig=(4096/3)pi
find radius
(4096/3)pi=(4/3)pir^3
divide both sides by pi
(4096/3)=(4/3)r^3
times both sides by 3
4096=4r^3
divide both sides by 4
1024=r^3
cube root both sides
8∛2=r
aprox
10.0794
the answer you are looking for is 8∛2 or 10.0794in or something close to that
Answer:
The correct answer is option a
Sin A = 2√13/13
Cos A = 3√13/13
Tan A = 2/3
Step-by-step explanation:
From the figure we can see that,a right angled triangle.
ΔABC
<u>To find side AB
</u>
AB = √(AC)² + (BC)² =√(36² - 24² )= √1872
AC = 12√13
<u> To find the trigonometric ratio
</u>
Sin A = BC/AB = 24/12√13 = 2√13/13
Cos A = AC/AB = 36/ 12√13 = 3√13/13
Tan A = BC/AC = 24/36 = 2/3
Answer:
d = √5 ≈ 2.24
Step-by-step explanation:
B is located at (1, 3) and B' is located at (3, 4)
Distance formula:
[tex] d = \sqrt{(xB' - xB)^2 + (yB' - yB)^2}[\tex]
replacing with the coordinates of the points:
[tex] d = \sqrt{(3 - 1)^2 + (4 - 3)^2}[\tex]
[tex] d = \sqrt{4 + 1}[\tex]
d = √5 ≈ 2.24
Answer:
(5d⁴ − 8)²
Step-by-step explanation:
I hope this is helpful!
Answer: You have to get rid of the variables (the x's) so subtract 2x from 2x and 11x then go from there.
Step-by-step explanation:
