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3 years ago

What is the length of the hypotenuse?

Mathematics

2 answers:

aniked [119]3 years ago

7 0

Answer:

c = 85 yards.

Step-by-step explanation:

Since this is a right triangle, we can use Pythagorean Theorem to solve for c.

$a^2+b^2=c^2\\51^2+68^2=c^2\\2601+4624=c^2\\7225=c^2\\\sqrt{7225}=c\\85=c$

klasskru [66]3 years ago

3 0

Answer:

85 yd

Step-by-step explanation:

As this is a right triangle, we can use the Pythagorean Theorem to find the length of the hypotenuse:

(51 yd)^2 + (68 yd)^2 = c^2, or:

(2601 + 4624) = c^2 = 7225

Then the length of the hypotenuse, c, is √7225 yd = 85 yd

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Answer:

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Step-by-step explanation:

Given

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Required

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3 years ago

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2 years ago

The hypotenuse of an isosceles right triangle is centimeters longer than either of its legs. Find the exact length of each side.

Varvara68 [4.7K]

Question

The hypotenuse of an isosceles right triangle is 11 centimeters longer than either of its legs. find the exact length of each side.

Answer:

$Hypotenuse:37.56$

$Other\ Legs: 26.56$

Step-by-step explanation:

Let the hypotenuse be y and the other legs be x.

So:

$y = 11 + x$

Required

Determine the exact dimension of the triangle

Using Pythagoras theorem;

$y^2 = x^2 + x^2$

$y^2 = 2x^2$

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$(11+x)^2 = 2x^2$

Open bracket

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Collect like terms

$2x^2 - x^2 -22x - 121 = 0$

$x^2 -22x - 121 = 0$

Using quadratic formula:

$x = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}$

$x = \frac{-(-22)\±\sqrt{(-22)^2 - 4*1*-121}}{2*1}$

$x = \frac{-(-22)\±\sqrt{968}}{2*1}$

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Split

$x = \frac{22+31.11}{2}\ or\ x = \frac{22-31.11}{2}\\$

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So:

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$y = 11 + 26.56$

$y = 37.56$

Hence, the dimensions are:

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