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3 years ago

The parallelogram shown below has an area of 72 units?. h 13 Find the missing height.

Mathematics

1 answer:

Vaselesa [24]3 years ago

6 0

Answer:

area is given base is given so area of parallelogram =b x h

or 72=13 x h

or h =72/13=5.5 units

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Here is a shape made from a rectangle and a triangle.

NISA [10]

Answer:

Area of shape = 187 cm²

Step-by-step explanation:

Given:

Length of rectangle = 15 cm

Width of rectangle = 9 cm

Height of triangle = (22-9) cm = 13 cm

Base of triangle = (15-7) cm = 8 cm

Find:

Area of shape

Computation:

Area of shape = Area of rectangle + Area of triangle

Area of shape = (l)(b) + (1/2)(b)(h)

Area of shape = (15)(9) + (1/2)(8)(13)

Area of shape = 135 + 52

Area of shape = 187 cm²

7 0

3 years ago

(b) For a function h(theta)=sin3 theta (Theta is in Radian). <br> Find h(pi/3)<br> Find h(pi/2)

vaieri [72.5K]

Part (i)

Plug in theta = pi/3 to get

h(theta) = sin(3theta)

h(pi/3) = sin(3*pi/3)

h(pi/3) = sin(pi)

h(pi/3) = 0 ... use a calculator or the unit circle

<h3>Answer: 0</h3>

=================================================

Part (ii)

Plug in h = pi/2

h(theta) = sin(3theta)

h(pi/2) = sin(3pi/2)

h(pi/2) = -1

<h3>Answer: -1</h3>

5 0

4 years ago

Please help!!<br> I’m so confused <br> And please don’t use the link joke

bagirrra123 [75]

Answer:

15u + 141 = 420

Step-by-step explanation:

So basically we are modelling how much the coach is spending. Each player is given a uniform and a basketball

We can use 'u' as the cost of a single uniform

We can use 'b' as the cost of a single basketball

Since there is 15 players we must give a ball and uniform to each so

15u + 15b = 420

The problem gives us the cost of each basketball: 9.40

so now 15u + 15(9.4) = 420

15u + 141 = 420

8 0

3 years ago

If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe

Natalka [10]

Answer:

They encircle the planet $3.76\times 10^{11}$ times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is $6.022\times 10^{23}$

Thus, the number of dust particles is:

$2.5\times 6.022\times 10^{23}=15.055\times 10^{23}$

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: $10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m$

If we line up the particles the distance they could cover is:

$15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}$

Circumference in meters:

$40,076km\times \frac{1000m}{1km}=40,076,000 m$

Therefore,

$\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}$

Hence, they encircle the planet $3.76\times 10^{11}$ times.

8 0

3 years ago

What is the sum?<br> 6x^7 + 8x^7

BaLLatris [955]

Since both terms have the same variable to the same power, you can simply add the coefficients...

14x^7

3 0

4 years ago

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