1. Think about a business opportunity that appeals to you. For this business, answer the six assessment questions listed in this
1 answer:
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Answer:
6.52%
Explanation:
For computing the nominal yield to call, first we have to find out the present value by applying the present value formula which is shown in the attachment below:
Future value = $1,000
Rate of interest = 6.50% ÷ 2 = 3.25%
NPER = 15 years × 2 = 30 years
PMT = $1,000 × 8.25% ÷ 2 = $41.25
The formula is shown below:
= -PV(Rate;NPER;PMT;FV;type)
So, after solving this, the present value is $1,166.09
Now to determine the yield to call we use the RATE formula that is shown in the attachment below:
Present value = $1,166.09
Future value or Face value = $1,120
PMT = $1,000 × 8.25% ÷ 2 = $41.25
NPER = 6 years × 2 = 12 years
The formula is shown below:
= Rate(NPER;PMT;-PV;FV;type)
The present value come in negative
So, after solving this, the bond nominal yield to call is
= 3.26% × 2 years
= 6.52%
Answer:
Since the calculated value of F= 5.733 falls in the critical region we reject the null hypothesis and conclude all three means are not equal.
Explanation:
The given data is
Banking Retail Insurance
12 8 10
10 8 8
10 6 6
12 8 8
<u>10 10 10</u>
The results of excel are:
<u><em>Anova: Single Factor </em></u>
SUMMARY
Groups Count Sum Average Variance
Column 1 5 54 10.8 1.2
Column 2 5 40 8 2
Column 3 5 42 8.4 2.8
1) Let the null and alternate hypotheses be
H0: u1=u2=u3 i.e all the three means are equal and
Ha: Not all three means are equal
2) The significance level is set at ∝ =0.05
3)The test statistic to use is
F= sb²/ sw²
which has F distribution with v1= k-1 →3-1=2 and v2= n-k →15-3=12 degrees of freedom
After calculations the following table is obtained.
<u><em>ANOVA </em></u>
Source SS df MS F P-value F crit
of Variation
B/w Groups 22.93 2 11.467 5.733 0.01788 3.885
<u>Within Groups 24 12 2 </u>
<u>Total 46.93 14 </u>
4) The critical region is F ≥ F(0.05, 2,12) = 3.885
5) Since the calculated value of F= 5.733 falls in the critical region we reject the null hypothesis and conclude all three means are not equal.
