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damaskus [11]
3 years ago
11

Hi can someone please help and explain to me how to do this with the answer? Will mark brainliest!

Mathematics
1 answer:
Otrada [13]3 years ago
6 0

Answer:

y=√x+5 -1

the answer is option C,,

x=-7,y=√-7+5 -1=√-2 -1

we can't find the square root of negative values, therefore it displays as error

x=-6,y=√-6+5-1=√-1 -1

same reason

x=-5,y=√-5+5-1=√0-1=-1

x=-4,y=√-4+5-1=√1-1=0

x=-1,y=√-1+5-1=√4-1=1

x=4,y=√4+5-1=√9-1=2

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Help meeeeeeeeeeeeeeeeeee<br><br> 10 poiiiiintsssss
11Alexandr11 [23.1K]

Answer: no i do not agree.

Step-by-step explanation:

Try n = 2 and you will see the answer

8(2) + 6

16 + 6

22

2{4(2) + 3}

2(8+3)

2(11)

22

14(2)

All 3 do not equal to each other. Proving that Juwon's statement is wrong.

6 0
3 years ago
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Solo necesito ayuda con las que están en amarillo las otras ya están realizadas
GalinKa [24]
Solo tienes que divide
4 0
3 years ago
HELP MEE BRAINLIEST PLZZZZ!!!!
wel

The 3rd one

This is because in the graph it’s looking for numbers 70-79 but only with 2 numbers and the 3rd is the only one that fits in the description.

8 0
3 years ago
I don’t know how to do this please helppp
Kitty [74]

Answer:

Given the 2 values, height and the base, of these 2 triangles, we can assume that they are similar (meaning they share the same angles) as we have no other information to determine the height of the tree.

Therefore, if these triangles are similar, their corresponding sides are proportional. In other words, PZ/RT = QZ/ST or RT/PZ=ST/QZ

Hence, if we find the ratio of this, we can use it to find the side <em>h</em>

<em>QZ/ST=PZ/RT</em>

<em>48/12=PZ/4</em>

<em>PZ/4=48/12</em>

<em>(PZ/4)3=48/12</em>

<em>PZ(3)/12=48/12</em>

<em>48/3=16</em>

16=PZ.

3Step-by-step explanation:

7 0
3 years ago
What is equivalent to -6 to the -5 power?
Anarel [89]

Answer:

-\frac{1}{7776}

Step-by-step explanation:

Put negative exponents in the denominator to make them positive.

\frac{1}{-6^5}

\frac{1}{-6*-6*-6*-6*-6}

\frac{1}{-7776}

-\frac{1}{7776}

8 0
3 years ago
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