Hi can someone please help and explain to me how to do this with the answer? Will mark brainliest!

Mathematics

1 answer:

Otrada [13]3 years ago

6 0

Answer:

y=√x+5 -1

the answer is option C,,

x=-7,y=√-7+5 -1=√-2 -1

we can't find the square root of negative values, therefore it displays as error

x=-6,y=√-6+5-1=√-1 -1

same reason

x=-5,y=√-5+5-1=√0-1=-1

x=-4,y=√-4+5-1=√1-1=0

x=-1,y=√-1+5-1=√4-1=1

x=4,y=√4+5-1=√9-1=2

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Number 36 plz I really need help please I will give you brainlist

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Step-by-step explanation:

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Relative extrema occur where the derivative is zero (at least for your polynomial function). So taking the derivative we get

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First year profits of a business were $900 . Second year profits were $1200 . What percent of the first year profits were the se

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Kristen needs to earn $320 in commission this week. She earns 8%

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She needs to sell $4,000 worth of merchandise.

If she needs to earn $320, and she earns 8% commission, you’re looking for what 8% of original amount equals $320.

X = original amount
8% = .08
$320 = amount needed

X * .08 = $320.
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Kristen needs to sell $4,000 worth of merchandise at an 8% commission rate to earn $320.

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3 years ago

Two cars start out together from the same place. they travel in opposite directions, with one of them traveling 5 miles per hou

Mashutka [201]

Annotation
General formula for distance-time-velocity relationship is as following
d = v × t
The velocity of the first car will be v₁, the time is 2 hours, the distance will be d₁.
The velocity of the second car will be v₂, the time is 2 hours, the distance will be d₂.

One of them traveling 5 miles per hour faster than the others. That means the velocity of the first car is 5 miles per hour more than the velocity of the second car.
v₁ = v₂ + 5 (first equation)

The distance of the two cars after two hours will be 262 miles apart. Because they go to opposite direction, we could write it as below.
d₁ + d₂ = 262 (second equation)

Plug the d-v-t relationship to the second equation
d₁ + d₂ = 262
v₁ × t + v₂ × t = 262
v₁ × 2 + v₂ × 2 = 262
2v₁ + 2v₂ = 262

Plug the v₁ as (v₂+5) from the first equation
2v₁ + 2v₂ = 262
2(v₂ + 5) + 2v₂ = 262
2v₂ + 10 + 2v₂ = 262
4v₂ + 10 = 262
4v₂ = 252
v₂ = 252/4
v₂ = 63
The second car is 63 mph fast.

Find the velocity of the first car, use the first equation
v₁ = v₂ + 5
v₁ = 63 + 5
v₁ = 68
The first car is 68 mph fast.

Answer
$\boxed{\boxed{ v_{1}=68mph} }$
$\boxed{\boxed{ v_{2}=63mph} }$

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