Answer:
YES
Step-by-step explanation:
Hey hey hey I see no picc
Answer:

There are two best ways to solve this.
using cosine method:




using sine method:




There are many ways, not to make it complex, these are the best ways to solve for n. Hope it helps ~
Y=-3x+2:
Already in slope intercept form
Graph by plotting a point on (0,2)
Then move 3 points up and 1 to the right and plot the point and keep doing that a couple times
-3x-y=-2:
Add -3x on both sides
The result would be
-y=3x-2
Divide everything by negative 1
Y=-3x+2
Both equations are the same so they are the same line
7x³ = 28x is our equation. We want its solutions.
When you have x and different powers, set the whole thing equal to zero.
7x³ = 28x
7x³ - 28x = 0
Now notice there's a common x in both terms. Let's factor it out.
x (7x² - 28) = 0
As 7 is a factor of 7 and 28, it too can be factored out.
x (7) (x² - 4) = 0
We can further factor x² - 4. We want a pair of numbers that multiply to 4 and whose sum is zero. The pairs are 1 and 4, 2 and 2. If we add 2 and -2 we get zero.
x (7) (x - 2) (x + 2) = 0
Now we use the Zero Product Property - if some product multiplies to zero, so do its pieces.
x = 0 -----> so x = 0
7 = 0 -----> no solution
x - 2 = 0 ----> so x = 2 after adding 2 to both sides
x + 2 = 0 ---> so = x - 2 after subtracting 2 to both sides
Thus the solutions are x = 0, x = 2, x = -2.