Find the value of (a+b)^2 if a^2+b^2=10 and ab=3
2 answers:
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Answer:
(b)
Step-by-step explanation:
Let E: Event of getting a 3 in the spinner.
So, the number of favorable outcomes = 11
Total number of outcomes = Number of times the outcomes is {1,2,3,4,5,6}
= {13 +10 +11+16+11} = { 61}
So, the total number of outcomes = 61
So, here
Answer with Step-by-step explanation:
Let us assume the 2 consecutive natural numbers are 'n' and 'n+1'
Thus the product of the 2 numbers is given by
We know that the sum of 'n' consecutive natural numbers starting from 1 is
Thus from equation 'i' we can write
As we know that any number multiplied by 2 is even thus we conclude that the product of 2 consecutive numbers is even.