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Lapatulllka [165]
2 years ago
10

What is the solution to this equation? 4(3x + 5) = 5(x + 4) + 7x

Mathematics
1 answer:
Artist 52 [7]2 years ago
3 0

Answer:

Step-by-step explanation:

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3 years ago
The following frequency table shows the number of cavities each of Dr. Freese's patients had.
Anit [1.1K]

Answer:

0

Step-by-step explanation:

13 patients had 0 cavities, according to the table! The righthand column is the frequency of people, and the left is the number of cavities they had.

6 0
3 years ago
Fractions, Decimals<br>Write each as a decimal<br>1) 90%​
andrey2020 [161]

Answer:

0.9

Step-by-step explanation:

90%

=90/100

=9/10

=0.9

4 0
3 years ago
The endpoints of a diameter of a circle are (6,2) and (−2,5) . What is the standard form of the equation of this circle?
Paul [167]

Answer:

The standard form of the given circle is

(x-2)^2+(y-\frac{7}{2})^2=73

Step-by-step explanation:

Given that the end points of a diameter of a circle are (6,2) and (-2,5);

Now to find the standard form of the equation of this circle:

The center is (h,k) of the circle is the midpoint of the given diameter

midpoint formula is M=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

Let (x_{1},y_{1}) and (x_{2},y_{2}) be the given points (6,2) and (-2,5) respectively.

M=(\frac{6-2}{2},\frac{2+5}{2})

M=(\frac{4}{2},\frac{7}{2})

M=(2,\frac{7}{2})

Therefore the center (h,k) is (2,\frac{7}{2})

now to find the radius:

The diameter is the distance between the given points (6,2) and (-2,5)

d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

=\sqrt{(-2-6)^2+(5-2)^2}

=\sqrt{(-8)^2+(3)^2}

=\sqrt{64+9}

=\sqrt{73}

Therefore the radius is \sqrt{73}

i.e., r=\sqrt{73}

Therefore the standard form of the circle is

(x-h)^2+(y-k)^2=r^2

Now substituting the center  and radiuswe get

(x-2)^2+(y-\frac{7}{2})^2=(\sqrt{73})^2

(x-2)^2+(y-\frac{7}{2})^2=73

Therefore the standard form of the given circle is

(x-2)^2+(y-\frac{7}{2})^2=73

5 0
3 years ago
A rectangle is 4.2 centimetres wide and each diagonal is 8.6 centimetres long. What is the measure of the angle between a diagon
CaHeK987 [17]

Answer:

60.8^\circ

Step-by-step explanation:

First, let's check side lengths.

Using the Pythagorean theorem we can find the length of the other side of the rectangle.

a^2 + b^2 = c^2

4.2^2 + b^2 = 8.6^2

b^2 = 56.32

b = 7.5

The other side of the rectangle measures 7.5 cm, so now we know that 4.2 cm is indeed the shorter side of the rectangle.

For the angle in question, the 4.2 cm side is the adjacent leg.

The diagonal of 8.6 cm is the hypotenuse.

The trig ratio that relates the adjacent leg to the hypotenuse is the cosine.

\cos \alpha = \dfrac{adj}{hyp}

\cos \alpha = \dfrac{4.2~cm}{8.6~cm}

\alpha = \cos^{-1} \dfrac{4.2~cm}{8.6~cm}

\alpha = 60.8^\circ

3 0
3 years ago
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