Answer:
-2
Step-by-step explanation:
when x=0 y=-2... it is a decline
Answer:
Step-by-step explanation:
Jason is not correct because 0.819 is not larger than 0.85. Marco's number is larger.
Answer:
nElements = 0;
for (int i = 0; i < a2d.length; i++)
nElements += a2d[i].length;
isRectangular = true;
for (int i = 1; i < a2d.length && isRectangular; i++)
if (a2d[i].length != a2d[0].length)
isRectangular = false;
Step-by-step explanation:
2 dimensional array is created and initialize element with 0. and the taking loop for 2 dimensional array .such as
n Elements = 0;
for (int i = 0; i < a2d.length; i++)
n Elements += a2d[i].length;
A boolean variable isRectangular and 2 dimensional array has been created if rectangle is true the take a2d.length and isRectangular less than i and intiliaze i with 1 then increment the i .It will give true value.
If rectangular is false then apply if statement and see if a2d[i] is not equal to a2d[0]
if (a2d[i].length != a2d[0].length)
isRectangular = false;
Well if you use graph paper you can graph the points you already have and then you can find the slope of the line easiest that way, the next point would be. (-1,8)
It’s a semicircle, so it would be 1/2 pi r^2.
