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2 years ago

Use the trend line to predict the wind chill at these wind speeds (9 and 10)

Mathematics

2 answers:

ValentinkaMS [17]2 years ago

8 0

Answer:

To do that select 2 points from your list and find the y = mx + b equation.

Step-by-step explanation:

vfiekz [6]2 years ago

5 0

First, you need to find the trend line that you are going to use before you can answer question 9 and 10.

To do that select 2 points from your list and find the y = mx + b equation.

After you have your equation, all you need to do is plug in the values that you are given for x. Evaluate the expression and you will have your answer.

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The larger of two numbers is 7 times the smaller number. Three times the larger number is 7 more than 4 times the smaller number

Juliette [100K]

Let the smaller number be x.

Given, the larger number is 7 times the smaller number.

So, the larger number = 7x.

Given, 3 times the larger number is 7 more than 4 times the smaller number.

So we can write the equation as,

$3(7x) = 4(x)+7$

$3(7x) = 4x+7$

$21x = 4x+7$

Now we have to move 4x to the left side by subtracting 4x from both sides.

$21x-4x = 4x-4x+7$

$21x-4x = 7$

$17x = 7$

To get x, we will divide both sides by 17. We will get,

$\frac{17x}{17} = \frac{7}{17}$

$x = \frac{7}{17}$

So the smaller number = $\frac{7}{17}$

The larger number = $7(\frac{7}{17} )$ = $\frac{49}{17}$

So we have got the required numbers.

Smaller number = $\frac{7}{17}$ and larger number = $\frac{49}{17}$ .

4 0

3 years ago

BRAINLY POINT CHALLENGE

elena-14-01-66 [18.8K]

Answer:

90ft2

Step-by-step explanation:

rectangle= BH

Triangle= BH/2

add em together and you get you're answer

(B is base and H is height)

3 0

2 years ago

In this exercise, T: R2 → R2 is a function. For each of the following parts, state why T is not linear. (a) T(a1, a2)= (1, a2) (

DENIUS [597]

Answer:

a) T is not homogeneous
b) T is not additive
c) T is not homogeneous
d) T is not additive
e) T is not additive

Step-by-step explanation:

In each case there is an example where one property of linear functions fails.

a) $T(2(1,0))=T((2,0))=(1,0); 2T((1,0))=2(1,0)=(2,0)$ . These vectors are not equal, then T doesn't satisfy the condition of scalar multiplication (homogeneity).

b) $T((1,2)+(2,3))=T(3,5)=(3,9); T((1,2))+T((2,3))=(1,1)+(2,4)=(3,5)$ . Because these vectors are not equal, T doesn't satisfy the property of vector addition (additivity).

c) $T(\frac{1}{2}(\pi,0))=T((\frac{\pi}{2},0))=(\sin(\frac{\pi}{2}),0)=(1,0); \frac{1}{2}T((\pi,0))=\frac{1}{2}(0,0)=(0,0)$ so T is not homogeneous.

d) $T((-1,0)+(1,0))=T(0,0)=(0,0); T((-1,0))+T((1,0))=(1,0)+(1,0)=(2,0)$ then T is not additive.

e) $T((0,0)+(1,0))=T(1,0)=(2,0); T((0,0))+T((1,0))=(1,0)+(2,0)=(3,0)$ then T is not additive.

8 0

2 years ago

Flying against the wind, a jet travels 4400mi in 8 hours. Flying with the wind, the same jet travels 5820mi in 6 hours. What is

Viefleur [7K]

Let J = rate of jet in still airLet W = rate of wind Distance formula: d = rt / r = d/t Flying against the wind the jet flies at a rate of J - W = 1860 miles/3 hours = 620 miles per hourFlying with the wind the jet flies at a rate of J+W = 9180 miles/9 hours = 1020 miles per hour The average of these 2 rate is the speed of the jet in still air J = (620+1020)/2 = 820 miles per hour J - W = 620

820 - W = 620
W = 820 - 620 = 200 miles per hour The jet in still air flies at a rate of 820 mph(miles per hour)The wind speed is 200 mph(miles per hour)

3 0

3 years ago

A random sample is drawn from a population with mean μ = 66 and standard deviation σ = 5.5. use table 1.

creativ13 [48]

<span>A random sample is drawn from a population with mean μ = 66 and standard deviation σ = 5.5. use table 1.
a. is the sampling distribution of the sample mean with n = 16 and n = 36 normally distributed? yes, both the sample means will have a normal distribution. no, both the sample means will not have a normal distribution. no, only the sample mean with n = 16 will have a normal distribution. no, only the sample mean with n = 36 will have a normal distribution.
b. can you use the standard normal distribution to calculate the probability that the sample mean falls between 66 and 68 for both sample sizes? yes, for both the sample sizes, standard normal distribution could be used. no, for both the sample sizes, standard normal distribution could not be used. no, only for the sample size with n = 16, standard normal distribution could be used. no, only for the sample size with n = 36, standard normal distribution could be used.
c. calculate the probability that the sample mean falls between 66 and 68 for n = 36. (round intermediate calculations to 4 decimal places, "z" value to 2 decimal places, and final answer to 4 decimal places.)</span>

7 0

3 years ago