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sammy [17]
3 years ago
9

A flagpole stands perpendicular to the ground. It is supported by a 20-foot cable that runs from the top of the flagpole to the

ground at a point that is 12 feet from the base of the pole. Find the height of the flagpole. The Pythagorean theorem is a2 b2
Mathematics
1 answer:
3241004551 [841]3 years ago
7 0

Answer:

h  =  16 feet

Step-by-step explanation:

Pythagoras´ theorem establishes, that in a right triangle square of the hypothenuse (c²) is the sum of leg ( b²)  plus  leg  (a²)

Then

c²  =  a²  +  b²

where according to the problem statement

(20)²  =  h²  +  (12)²           (  h is the height of the flagpole )

h²  =  400 -  144

h²  =  256

h  =  √ 256

h  =  16 feet

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The perimeter of a rectangular field is 60ft and its width is 20ft find the area of this field
Gennadij [26K]

Perimeter of rectangle = 2( length +width)

given: Perimeter=60 ft and width=20 ft

plugging these values in the formula,

60=2(20+ length)

dividing both sides by 2

30=20+length

length =30-20=10

length is 10 feet

width is 20 feet

Area of rectangle is given by:

Area = l*w

Area = 10 *20 = 200 square feet

Answer : Area of rectangle is 200 square feet.

4 0
3 years ago
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If it takes 5 years for an animal population to double, how many years will it take until the population
muminat

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Answer:

  7.92 years

Step-by-step explanation:

We want to find t such that ...

  3 = 2^(t/5)

where 2^(t/5) is the annual multiplier when doubling time is 5 years.

Taking logs, we have ...

  log(3) = (t/5)log(2)

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It will take about 7.92 years for the population to triple.

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There are 6 ants on a log. Then 7 ants crawl onto the log. How many ants are on the log now?
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At Western University the historical mean of scholarship examination scores for freshman applications is 900. A historical popul
vampirchik [111]

Answer:

a) Null Hypothesis: \mu =900

Alternative hypothesis: \mu \neq 900

b) The 95% confidence interval would be given by (910.05;959.95)    

c) Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d) z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750

Since is a bilateral test the p value is given by:

p_v =2*P(Z>2.750)=0.0059

Step-by-step explanation:

a. State the hypotheses.

On this case we want to check the following system of hypothesis:

Null Hypothesis: \mu =900

Alternative hypothesis: \mu \neq 900

b. What is the 95% confidence interval estimate of the population mean examination  score if a sample of 200 applications provided a sample mean x¯¯¯= 935?

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=935 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=180 represent the population standard deviation

n=200 represent the sample size  

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=3278.222

The sample deviation calculated s=97.054

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

935-1.96\frac{180}{\sqrt{200}}=910.05    

935+1.96\frac{180}{\sqrt{200}}=959.95    

So on this case the 95% confidence interval would be given by (910.05;959.95)    

c. Use the confidence interval to conduct a hypothesis test. Using α= .05, what is your  conclusion?

Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d. What is the p-value?

The statistic is given by:

z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

If we replace we got:

z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750

Since is a bilateral test the p value is given by:

p_v =2*P(Z>2.750)=0.0059

So then since the p value is less than the significance we can reject the null hypothesis at 5% of significance.

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