I would use the quadratic formula for this:
x = -b ± √b² - 4ac over 2a
x = 8 ± √64 - 4(1)(0) over 2(1)
x = 8 ± √64 over 2
x = 8 <span>± 8 over 2 [simplify]
x = 4 </span><span>± 4
x1 = 4 + 4 x2 = 4 - 4
x1 = 8 x2 = 0
Thus, the solutions for x would be 0 and 8.</span>
Answer:
12
Step-by-step explanation:
So, all you have to do is multiply 6 and 2.
In 
If you add + it equals 1 whole.
If 2 equals 1 whole. You multiply 6 by 2.
Hope this helped!
Answer:
(-8,4)
Step-by-step explanation:
Given: 2x-3y=-28 and x+6y=16
solve for a variable and then substitute back into other equation
x + 6y = 16
x = 16 - 6y; now use this in the other equation
2x - 3y = -28; substitute into x
2(16 - 6y) - 3y = -28; distribute 2
32 - 12y - 3y = -28; combine y's
32 - 15y = -28; isolate 15y
32 + 28 = 15y; add the numbers
60 = 15y; divide by 15
y = 4
Now use this to plug into other equation
x + 6y = 16; y=4
x + 6(4) = 16;
x + 24 = 16; subtract 24 from both sides
x = -8
Answer:
d
Step-by-step explanation:
A(n) = 1 - 0.1(n-1)
A(1) = 1- 0.1*(1-1) = 1 - 0.1*0 = 1
A(2) = 1- 0.1*(2-1) = 1 - 0.1*1 = 1- 0.1 = 0.9
A(3) = 1 - 0.1(3-1) = 1 - 0.1*2 = 1-0.2=0.8
Method:
A(1)=1
D = A(2)-A(1) = 0.9 - 1 = -0.1
A(n) = A(1)+(n-1)*d = 1 + (n-1)*(-0.1)
= 1 - 0.1(n -1)
