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KATRIN_1 [288]
3 years ago
13

this table shows input and output values for a linear function f(x). What is the difference of outputs for any two inputs that a

re one value apart?

Mathematics
2 answers:
Lapatulllka [165]3 years ago
7 0

Answer: The answer is (c) 0.5.

Step-by-step explanation:  We are given a table that shows the input and output values of a function f(x). We are to find the difference of outputs for any two inputs that are one value apart.

That is, we need to find f(n + 1) - f(n), for n > -4.

Let us take n = 0. So, n + 1 = 0.

From the table, we note that f(0) = 1  and  f(1) = 1.5.

Therefore, we have

f(1)-f(0)=1.5-1=0.5.

We can also check taking different values of 'n' that the difference will come out to be same, i.e., 0.5.

Thus, the answer is 0.5.

Solnce55 [7]3 years ago
5 0
The answer is 0.5.

X is the input and f(x) is the output. Between -3 and -2 the difference is 0.5. Because it goes from -0.5 to 1
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Given that -15 is a root of x² +mx +45 = 0 find the constant m​
o-na [289]

Answer:

m = 18

Step-by-step explanation:

Given :

=> -15 is a root of the polynomial

=>  It is a zero to the solution.

Process :

Substitute -15 in place of x.

=> (-15)² + (-15)m + 45 = 0

=> 225 + 45 - 15m = 0

=> 15m = 270

=> m = 270/15

=> m = 18

5 0
3 years ago
Susan paid $15.84 for a 7.48 - kg bag of dog food. A few weeks later, she paid $16.58 for a 7.94 - kg bag at a different store.
barxatty [35]

The unit price for the 7.48 is $2 kg per bag and the unit price for the 7.94 is $2 per kg bag, there is no difference in unit rates of both the bag.

<h3>What is unit rate?</h3>

A unit rate means a rate for one of something.

Given that, Susan paid $15.84 for a 7.48 kg bag of dog food. A few weeks later, she paid $16.58 for a 7.94 kg bag at a different store.

15.48/7.48 = $2/kg

16.58/7.94 = $2/kg

Hence, there is no difference in between both the bags, hence either of them are better.

For more references on unit rates, click;

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4 0
1 year ago
A lottery game has balls numbered 1 through 21. What is the probability of selecting an even numbered ball or an 8? Round to nea
Viktor [21]

Answer: 0.476

Step-by-step explanation:

Let A = Event of choosing an even number ball.

B = Event of choosing an 8 .

Given, A lottery game has balls numbered 1 through 21.

Sample space: S= {1,2,3,4,5,6,7,8,...., 21}

n(S) = 21

Then, A= {2,4,6,8, 10,...(20)}

i.e. n(A)= 10

B= {8}

n(B) = 1

A∪B = {2,4,6,8, 10,...(20)} = A

n(A∪B)=10

Now, the probability of selecting an even numbered ball or an 8 is

P(A\cup B)=\dfrac{n(A\cup B)}{n(S)}

=\dfrac{10}{21}\approx0.476

Hence, the required probability =0.476

7 0
3 years ago
Simplify the product by using FOIL <br><br> (6x-5)(2x-3)
Lapatulllka [165]

12x²-8x-15 should be your answer

3 0
3 years ago
Suppose that a large mixing tank initially holds 100 gallons of water in which 50 pounds of salt have been dissolved. Another br
Serggg [28]

Answer:

dA/dt = 12 - 2A/(100 + t)

Step-by-step explanation:

The differential equation of this problem is;

dA/dt = R_in - R_out

Where;

R_in is the rate at which salt enters

R_out is the rate at which salt exits

R_in = (concentration of salt in inflow) × (input rate of brine)

We are given;

Concentration of salt in inflow = 4 lb/gal

Input rate of brine = 3 gal/min

Thus;

R_in = 4 × 3 = 12 lb/min

Due to the fact that solution is pumped out at a slower rate, thus it is accumulating at the rate of (3 - 2)gal/min = 1 gal/min

So, after t minutes, there will be (100 + t) gallons in the tank

Therefore;

R_out = (concentration of salt in outflow) × (output rate of brine)

R_out = [A(t)/(100 + t)]lb/gal × 2 gal/min

R_out = 2A(t)/(100 + t) lb/min

So, we substitute the values of R_in and R_out into the Differential equation to get;

dA/dt = 12 - 2A(t)/(100 + t)

Since we are to use A foe A(t), thus the Differential equation is now;

dA/dt = 12 - 2A/(100 + t)

5 0
3 years ago
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