2 years ago

Find the number of solutions of the equation 6x^2+6x+3=0 by using the discriminant

Mathematics

1 answer:

Neporo4naja [7]2 years ago

4 0

Answer:

No real roots

Step-by-step explanation:

Given

$6x^2 + 6x + 3 = 0$

Required

The number of solution

The discriminant (d) for $ax^2 + bx + c = 0$ is:

$d = b^2 - 4ac$

So, we have:

$d = 6^2 - 4*6*3$

$d = 36 - 72$

$d = -36$

Since $d$ , then the equation has no real roots

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