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Natasha2012 [34]
2 years ago
9

Find the number of solutions of the equation 6x^2+6x+3=0 by using the discriminant

Mathematics
1 answer:
Neporo4naja [7]2 years ago
4 0

Answer:

No real roots

Step-by-step explanation:

Given

6x^2 + 6x + 3 = 0

Required

The number of solution

The discriminant (d) for ax^2 + bx + c = 0 is:

d = b^2 - 4ac

So, we have:

d = 6^2 - 4*6*3

d = 36 - 72

d = -36

<em>Since </em>d<em>, then the equation has no real roots</em>

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