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Likurg_2 [28]
2 years ago
6

I have a question.... my teacher today in biology said " you think you are moving your hand by yourself, but it's actually your

brain sending commands to your muscles so they can move." So I wondered.. is my brain sending commands so I can think, or am I thinking whenever I have a desire to? (Not a trick question; My friend thinks this is a trick question lol).
Biology
1 answer:
kow [346]2 years ago
3 0

Answer:

you are think of a command and your brain respond to you desire

Explanation:

You might be interested in
PLEASE HELP ASAP
il63 [147K]
I took this quiz the answer is C, protiens
8 0
3 years ago
Which capillary would be least likely to allow substances to enter or exit the blood due to tight junctions that join the endoth
vodka [1.7K]

Answer:

Those capillaries that have endothelial cells tightly attached have an increase in cell-to-cell junctions, such as desmosomal junctions that are poorly permeable to substances.

These capillaries generally function as conductors or collectors and not as permeabilizers like the pulmonary capillaries that are fenestrated and allow a high passage of substances and gases.

The capillaries are waterproof and prevent the passage of substances or fluids such as in the blood-brain barrier that is very selective

Explanation:

The blood-brain barrier is too selective since it is not favorable for the organism that many fluids, drugs, substances or chemical compounds enter the brain space.

This is the reason why the vessels are waterproof and why pharmacology was challenged to invent drugs that could cross this barrier since it was considered impossible.

An example is dopamine, which in parkynson's disease the levo group is added to dopamine, thus forming levodopamine as a product, this is the only way that the drug crosses the blood-brain barrier and can pass the impermeable barrier generated by capillaries with endothelial cells that are close to each other or closely linked

7 0
2 years ago
Imagine that a newly discovered, recessively inherited disease is expressed only in individuals with type O blood, although the
erastova [34]

Complete question:

Imagine that a newly discovered, recessively inherited disease is expressed only in individuals with type O blood, although the disease and blood group are independently inherited.

A normal man with type A blood and a normal woman with type B blood have already had one child with the disease. The woman is now pregnant for a second time.

Assuming that both parents are heterozygous for the gene that causes the disease, what is the probability that the second child will also have the disease? Express your answer as a fraction using the slash symbol and no spaces (for example, 1/2).

Answer:

The probability that the second child will also have the disease is 1/16.

Explanation:

<u>Available data:</u>

  • Two genes independently inherited: one for blood type, the other for disease
  • Man with type A blood  x  Woman with type B blood
  • Both parents are heterozygous for the gene that causes the disease; Dd

If the man has A blood, and the woman has B blood, and they already have an affected child, this means that they must be heterozygous for blood type too.

Cross:  

Parentals)           AiDd         x      BiDd

Gametes)  AD  Ad  iD  id       BD  Bd  iD  id

Punnett square)      AD       Ad       iD       id

                     BD   ABDD  ABDd  BiDD BiDd

                     Bd   ABDd   ABdd   BiDd Bidd

                     iD    AiDD    AiDd    iiDD   iiDd

                     id    AiDd     Aidd     iiDd    iidd

F1) <u>Genotype</u>:

1/16 ABDD

2/16 ABDd

1/16 ABdd

1/16 AiDD

1/16 BiDD

2/16 AiDd

2/16 BiDd

1/16 Aidd

1/16 Bidd

1/16 iiDD

2/16 iiDd

1/16 iidd

<u>Phenotype:</u>

3/16 A/B normal

4/16 A normal

4/16 B normal

3/16 0 normal

1/16 0 affected by the disease.

3 0
2 years ago
NEED ANSWER ASAP SOMEONE HELP PLS
Sholpan [36]

Answer:

a 1/4 there you go(;!!!

7 0
2 years ago
Read 2 more answers
What effect would there be on the final daughter cell if the spindle fibers failed to pull a chromosome toward the pole, as in c
allochka39001 [22]

Aneuploidy can result in the final daughter cell if the spindle fibers fail to pull a chromosome toward the pole as in case of non-disjunction.  

Explanation:

Aneuploidy is a condition which arises when one or more chromosome is missing in the final daughter cells.

Non-disjunction refers to the failure of chromosomal or chromatid segregation or separation during cell division. This results in erroneous meiosis or mitosis leading to the formation of final daughter cells or gametes with an extra or missing chromosome. This condition is aneuploidy.  

Failure of separation or segregation of:

  • Homologous chromosomes occur in Anaphase I, affects four daughter cells.
  • Sister chromatids during Anaphase II, affects two daughter cells

This failure of separation leads to aneuploidy chromosomal abnormalities like monosomy, trisomy, etc which can cause diseases like Down’s syndrome, Turner’s syndrome etc.

8 0
2 years ago
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