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Lelechka [254]
3 years ago
14

The left side of a solid block is held at a constant temperature of 200°C. The temperature profile within the block is given by

T=200−5x−x2 where x is the distance from the left side of the block in centimeters and T is the temperature in degrees Celsius of the block at location x. At what value of x is T=50°C?
Mathematics
1 answer:
Nikitich [7]3 years ago
6 0

Answer:

with T = 50⁰C, we have:

50 = 200 - 5x - x²

<=> x² + 5x = 150

<=> x² + 5x - 150 = 0

=> x = 10

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Step-by-step explanation:

<em>Hi</em><em> </em><em>there</em><em>!</em><em>!</em><em>!</em><em> </em>

<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>option A</em><em>. </em>

<em>reason</em><em> </em><em>look</em><em> </em><em>in</em><em> </em><em>picture</em><em>.</em><em> </em>

<em>if</em><em> </em><em>you</em><em> </em><em>want</em><em> </em><em>to</em><em> </em><em>solve</em><em> </em><em>it</em><em> </em><em>just</em><em> </em><em>cross</em><em> </em><em>multiply</em><em> </em><em>it</em><em>,</em>

<em>60x = 240000 \times 100</em>

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<em>Hope</em><em> </em><em>it helps</em><em>.</em><em>.</em><em>.</em>

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