Answer:
_____________________________
l l
l l
l l
l l
l____________________________l
In standard form:
answer- 14,000 and 12,000
Example
←LEFT 12,000
↑
comma(THOUSANDS PLACE)
ten thosands is the second number after the comma(thousands) to the left
<h2>
Explanation:</h2><h2>
</h2>
An irrational number is a number that can't be written as a simple fraction while a rational number is a number that can be written as the ratio of two integers, that is, as a simple fraction. So in this case we have the number 2 which is ration, and we can multiply it by an irrational number
such that the product is an irrational number. So any irrational number will meet our requirement because the product of any rational number and an irrational number will lead to an irrational number. For instance:

Answer:
Ans: H and A
Step-by-step explanation:
By the identity:
1-(cos(x))
Ans: H
For second quesiton, the transformation of a graph is that:
f(x) + k means vertical translation up by k units
Two curve have the same maximum value, so the graph doesn't translate upwards or downwards, thus b=0
Ans: A
By definition of absolute value, you have

or more simply,

On their own, each piece is differentiable over their respective domains, except at the point where they split off.
For <em>x</em> > -1, we have
(<em>x</em> + 1)<em>'</em> = 1
while for <em>x</em> < -1,
(-<em>x</em> - 1)<em>'</em> = -1
More concisely,

Note the strict inequalities in the definition of <em>f '(x)</em>.
In order for <em>f(x)</em> to be differentiable at <em>x</em> = -1, the derivative <em>f '(x)</em> must be continuous at <em>x</em> = -1. But this is not the case, because the limits from either side of <em>x</em> = -1 for the derivative do not match:


All this to say that <em>f(x)</em> is differentiable everywhere on its domain, <em>except</em> at the point <em>x</em> = -1.