The answer i got was 49-9b^2
Answer:
![\huge\boxed{Answer\hookleftarrow}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7BAnswer%5Chookleftarrow%7D)
<h3>✏
<u>cm²</u></h3>
⋆┈┈。゚❃ུ۪❀ུ۪❁ུ۪❃ུ۪❀゚ུ۪。┈┈⋆
<u>Given</u>:
Given that the surface area of the cone is 54 square inches.
We need to determine the surface area of the cone that is similar to the cone three times large.
<u>Surface area of the similar cone:</u>
Let us determine the surface area of the similar cone.
The surface area of the similar cone can be determined by multiplying the surface area of the cone by 3. Because it is given that the similar cone is three times large.
Thus, we have;
![SA = 3 \times 54](https://tex.z-dn.net/?f=SA%20%3D%203%20%5Ctimes%2054)
![SA=162](https://tex.z-dn.net/?f=SA%3D162)
Thus, the surface area of the similar cone is 162 square inches.
Answer:
associative property with respect to addition and subtraction
3+[7+(-4)]=(3+7)+(-4)
3+[7-4]=10+(-4)
3+3=10-4
6=6
Step-by-step explanation:
i hope it will help you
First, you add up the total number of students because we would base our percentage one this.
Total number of students = 1+4+5+10+20+10+5
Total number of students = 55
Now, let's count how many of them got a score of more than 70. For this, you would only count the students belonging to 70-under 80, 80-under 90 and 90-under 100.
Students who got more than 70 = 20+ 10 + 5 = 35
Therefore the percentage is equal to:
Percentage = 35/55 * 100 = 63.64%