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lianna [129]
2 years ago
13

Mrs. Hanger is painting the following picture of an H to hang in the entryway of her home. She has made the following scale draw

ing as her model. The scale used on the drawing is 1:6.
As you can see, the "H" is going to be painted brick red in the center of a rectangular beige background. This means the distance from the "H" to the top of the picture will be the same as the distance from the "H" to the bottom of the picture. Similarly, the distance from the "H" to the left side of the picture will be the same as the distance from the "H" to the right side of the picture. Finally, each segment of the "H" will have the same width.


QUESTION. :

1. Use the actual dimensions of the painting to find the percentage of the painting that will be beige. Explain your reasoning and show all calculations.

Mathematics
2 answers:
77julia77 [94]2 years ago
8 0

Answer:

40 square inch

Step-by-step explanation:

1/2+1/2= 1

1+1=2

2times 4= 8

8times 5= 40

if the problem has inches in it,

the answer will always equal to a square-inch

solong [7]2 years ago
8 0

Answer:

40 square inch

Step-by-step explanation:

1/2+1/2= 1

1+1=2

2 times 4= 8

8 times 5= 40

if the problem has inches in it,

the answer will always equal to a square-inch

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3629 you can use the digits twice make the largest four digit number​
Alex Ar [27]

Answer:

9632

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9966

Step-by-step explanation:

im not 100% sure

3 0
3 years ago
Junnie walked for 2.5 hours at a speed of 3.miles per hour. How far did Junnie walk?
Leona [35]

Answer:

7.5 miles

Step-by-step explanation:

2.5 times 3

hope this can help you :-P

8 0
3 years ago
Read 2 more answers
At an airport, 76% of recent flights have arrived on time. A sample of 11 flights is studied. Find the probability that no more
I am Lyosha [343]

Answer:

The probability is  P( X \le 4 ) = 0.0054

Step-by-step explanation:

From the question we are told that

   The percentage that are on time is  p =  0.76

   The  sample size is n =  11

   

Generally the percentage that are not on time is

     q =  1- p

     q =  1-  0.76

     q = 0.24

The  probability that no more than 4 of them were on time is mathematically represented as

        P( X \le 4 ) =  P(1 ) +  P(2) + P(3) +  P(4)

=>     P( X \le 4 ) =  \left n } \atop {}} \right.C_1 p^{1}  q^{n- 1} +   \left n } \atop {}} \right.C_2p^{2}  q^{n- 2} +  \left n } \atop {}} \right.C_3 p^{3}  q^{n- 3}  +  \left n } \atop {}} \right.C_4 p^{4}  q^{n- 4}

P( X \le 4 ) =  \left 11 } \atop {}} \right.C_1 p^{1}  q^{11- 1} +   \left 11 } \atop {}} \right.C_2p^{2}  q^{11- 2} +  \left 11 } \atop {}} \right.C_3 p^{3}  q^{11- 3}  +  \left 11 } \atop {}} \right.C_4 p^{4}  q^{11- 4}

P( X \le 4 ) =  \left 11 } \atop {}} \right.C_1 p^{1}  q^{10} +   \left 11 } \atop {}} \right.C_2p^{2}  q^{9} +  \left 11 } \atop {}} \right.C_3 p^{3}  q^{8}  +  \left 11 } \atop {}} \right.C_4 p^{4}  q^{7}

= \frac{11! }{ 10! 1!}  (0.76)^{1}  (0.24)^{10} +   \frac{11!}{9! 2!}  (0.76)^2 (0.24)^{9} + \frac{11!}{8! 3!}  (0.76)^{3}  (0.24)^{8}  + \frac{11!}{7!4!}  (0.76)^{4}  (0.24)^{7}

P( X \le 4 ) = 0.0054

4 0
3 years ago
If the members of the team are selected at random, what is the probability that 2 men and 2 women will be selected?
Norma-Jean [14]
N1=4,P 1=0.5.50 THINK
4 0
3 years ago
Josiah bought 22 chicken wings for $26.40. How much would it cost for 9 wings?
cricket20 [7]

Answer:

it would cost $10.8 for 9 chicken wings.

Step-by-step explanation:

Cost of 22 chicken wings = $26.40

we have to find first, cost of 1 chicken wings

For that we divide both side by 22

cost of 22/22 chicken wings = $26.40/22 = 1.2

Thus, cost of 1 chicken wings = $1.2

to fins cost of 9 chicken wings

we multiply both sides by 9

cost of 1*9 chicken wings = $1.2*9

cost of 9 chicken wings = $10.8

Thus, it would cost $10.8 for 9 chicken wings.

7 0
3 years ago
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