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Dahasolnce [82]
3 years ago
8

The shown quadrilateral is a rectangle. If AB is 10 what is the length of DC?

Mathematics
2 answers:
nirvana33 [79]3 years ago
8 0
The picture is black put it again and I’ll help for brainliest
baherus [9]3 years ago
4 0

Answer:

sir the picture is black

Step-by-step explanation:

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Can someone help me with this question please?
Verizon [17]
Is x=1/3 a possible answer? It would be if in fraction form.
or -31.

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3 years ago
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Sarahs craft project uses peices of yarn that are 1/8 yard long.She has a peice of yarn that is 3 yards ling.How many 1/8 yard p
motikmotik
Pieces of yarn .... 1/8 yard long (each)
a piece of yarn ... n = 3 yards long
remaining ... 1 1/4 yards = 5/4 yards

If you would like to calculate how many 1/8 yard pieces can Sarah cut and still have 1 1/4 yards left, you can do this using the following steps:

n - 1 1/4 = <span>3 - 1 1/4 </span>= 3 - 5/4 = 12/4 - 5/4 = 7/4 = 1 3/4 yards

7/4 / 1/8 = 7/4 * 8/1 = 14 pieces

Result: Sarah can cut 14 1/8 yard pieces and still have 1 1/4 yards left.

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4 years ago
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What is the standard form to number 3
Leto [7]
What’s number three?
7 0
3 years ago
What is the domain of g?
lawyer [7]

Answer:

A choice.

Step-by-step explanation:

Domain starts at x = - 7 and ends at x = 4. The domain from the graph is also continuous. Therefore, we can rule out C and D.

B is not correct as domain starts from x = -7 and not x = - 4.

8 0
3 years ago
Plz guys help i need asap<br> its part b im stuck
aleksklad [387]

Answer:

a.2nd quarter with 9 goals

b. 4.8 goals

c. 4 goals

Step-by-step explanation:

a. The mode is defined as the most appearing data point or the data point with the highest frequency..

From our data(for away goals):

  • 1st quarter-2
  • 2nd quarter-9
  • 3rd quarter-7
  • 4th quarter-4

Hence, the 2nd quarter has the mode for away goals with 9 goals.

b. Mean is defined as the average of a set of data points.

#We calculate the totals goals per quarter, sum over all quarters then divide by the number of games, 10:

\bar x=\frac{1}{n}\sum{x_i}\\1^{st }_g=Away+Home=5+2=7\\\\2^{nd}_g=Away+Home=4+9=13\\\\3^{rd}_g=Away+Home=8+7=15\\\\4^{th}_g=Away+Home=9+4=13\\\\\bar x=\frac{1}{n}\sum{x_i}=\frac{1}{10}(7+13+15+13)=4.8

Hence, the mean number of goals per quarter is 4.8 goals

c. To find the number of more home goals than away goals, we subtract from their summations as:

g_m=\sum{g_h}-\sum{g_a}\\\\=(5+4+8+9)-(2+9+7+4)\\\\=26-22\\\\=4

Hence, there are 4 more home goals than away goals.

4 0
3 years ago
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