3 years ago

What is the series of xcosx

Mathematics

1 answer:

AlladinOne [14]3 years ago

5 0

<span>the series of xcosx is x summation from k = 0 to k = infinity of ((-1)^k x^2k)/(2k)!</span>

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Point A is located at negative 5 over 8 and point B is located at negative 2 over 8. What is the distance between points A and B

ki77a [65]

<h2>Answer:</h2>

Option: A is the correct answer.

A. negative 5 over 8 minus negative 2 over 8 = negative 3 over 8; therefore, the distance from A to B is absolute value of negative 3 over 8 equals 3 over 8 units.

<h2>Step-by-step explanation:</h2>

The location of Point A is : A(-5/8)

and Point B is located at : B(-2/8)

We know that when two points lie over a number line then the distance between the two points is the absolute difference between the two points.

If A is located at a.

and B is located at b.

Then the distance between A and B is given by:

|a-b|

Hence, here the distance between A and B is given by:

$|\dfrac{-5}{8}-(\dfrac{-2}{8})|=|\dfrac{-5}{8}+\dfrac{2}{8}|=|\dfrac{-3}{8}|=\dfrac{3}{8}\\\\i.e.\\\\\text{Distance between A and B is}=\dfrac{3}{8}\ \text{units}$