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irina [24]
3 years ago
8

The university is trying to compile a visual display of the different majors of honor roll students which type of display will g

ive them the best picture of her students data
Mathematics
2 answers:
nordsb [41]3 years ago
4 0
I believe that the answer to the question provided above is that the <span>type of display will give them the best picture of her students data is a bar graph.</span>
Hope my answer would be a great help for you.    If you have more questions feel free to ask here at Brainly.
Alika [10]3 years ago
4 0

Answer:

Bar Graph

Step-by-step explanation:

Since University has to display different majors of honor roll students. The best representation for this type of data is the Bar graph.

As <em>Bar graph</em> shows the heights of different categorical data by the bar.

Here Different numbers of majors will be shown in one axis and honor roll students will be shown in one axis.

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finlep [7]

Answer:

2(3x+6), 6(x+2), and 3(2x+4)

Step-by-step explanation:

8 0
3 years ago
The perimeter of a rectangle is 50 inches. The length of the rectangle is 10 inches. Which
VMariaS [17]

Answer:15

Step-by-step explanation:

Solve for w in the equation 2w + 10 =50.

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2 years ago
plz help 20 pointssss!!!!!! The length of one edge of a cube is 3 units. What is the volume of this cube in units? A) 6 cubic un
marshall27 [118]

Answer:

See answer below

Step-by-step explanation:

Hi there,

The volume of a cube is the edge length cubed:

V = a³

The edge length given is 3 u, so plug into the formula:

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3 years ago
Read 2 more answers
What number to the power of 3 equals 27 over 729
Olin [163]

Answer:

x=  1/3 =0.333

Step-by-step explanation:

6 0
3 years ago
A. Find the linear approximating polynomial for the following function centered at the given point a. b. Find the quadratic appr
Tema [17]

Answer:

a. p1(x) = 2 - x

b. p2(x) = x² - 3*x + 3

c. p1(0.97) = 1.03; p2(0.97) = 1.0309

Step-by-step explanation:

f(x) = 1/x

f'(x) =  -1/x²

f''(x) = 2/x³

a = 1

a. The linear approximating polynomial is:

p1(x) = f(a) + f'(a)*(x - a)

p1(x) = 1/1 + -1/1² * (x - 1)

p1(x) = 1 - x + 1

p1(x) = 2 - x

b. The quadratic approximating polynomial is:

p2(x) = p1(x) + 1/2 * f''(a)*(x - a)²

p2(x) = 2 - x + 1/2 * 2/1³ * (x - 1)²

p2(x) = 2 - x + (x - 1)²

p2(x) = 2 - x + x² - 2*x + 1

p2(x) = x² - 3*x + 3

c. approximate 1/0.97 using p1(x)

p1(0.97) = 2 - 0.97 = 1.03

approximate 1/0.97 using p2(x)

p2(0.97) = 0.97² - 3*0.97 + 3 = 1.0309

7 0
3 years ago
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