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insens350 [35]
3 years ago
12

Help me plz i dont get it its alot ill mark brainliest​

Mathematics
1 answer:
Tanzania [10]3 years ago
7 0

Answer:

I CANT SEE IT sorry caops

Step-by-step explanation:

if i could see i could answer

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What is opposite of 6.8?​
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-6.8

Step-by-step explanation:

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Given the figure below, find the values of x and z.<br> 29<br> (8x + 37) •<br> (10x - 1)
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idk

Step-by-step explanation:

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Tom is buying topsoil for the flower bed shown below. One bag of topsoil covers 151515 square meters. How many bags of topsoil d
exis [7]

Answer:

2 bags of topsoil.

Step-by-step explanation:

The attached figure shows a flower bed.

One bag of topsoil covers 15 square meters.

We need to find how many bags of topsoil does Tom need to cover his flower bed.

The area of the flower bed is :

A=\dfrac{1}{2}\times 12\times 5\\\\=30\ m^2  

Let he has to cover x bags of topsoil. So,

x = Area of flower bed/Area of 1 bag of top soil

x = 30/15

x = 2

Hence, he will need 2 bags of topsoil to cover his flower bed.

6 0
3 years ago
In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that
attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable X\sim Poisson(\lambda = 0.62).

The probability function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

             = 1 - P (X = 0) - P (X = 1)

             =1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: \lambda=7\times0.62=4.34

Compute the probability of no deaths in a corps over 7 years as follows:

P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

6 0
3 years ago
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