1/4 goes into 2 2 /4
Means 2 2/4 divided by 1/4
Change 2 2 /4 to improper fraction. = (2*2 + 4)/4 = 10/4
10/4 ÷ 1/4
10/4 × 4/1
= 10
So it is 10.
F: R → R is given by, f(x) = [x]
It is seen that f(1.2) = [1.2] = 1, f(1.9) = [1.9] = 1
So, f(1.2) = f(1.9), but 1.2 ≠ 1.9
f is not one-one
Now, consider 0.7 ε R
It is known that f(x) = [x] is always an integer. Thus, there does not exist any element x ε R such that f(x) = 0.7
So, f is not onto
Hence, the greatest integer function is neither one-one nor onto.
The answer was quite complicated but I hope it will help you.
Answer:
G(x+2) = 7x^2 + 33x + 30
Step-by-step explanation:
So in the G(x) function, to find G(x+2), we just simply plug in the value of x+2 into the function and the result is what is wanted. SO:
G(x+2) = 7(x+2)^2 + 5(x+2) -8 , which is 7x^2 +33x +30 after SIMP - lifying (see what I did there ;)
Hope i helped, please make this brainly. :)
So when solving this you are going to have to solve the equation.
Okay so first thing we need to do is simplify both sides of your equation so:
3x−5=<span>2x+8+x
</span>Simplifying process:
<span><span><span>3x</span>+</span>−5</span>=<span><span><span>2x</span>+8</span>+<span>x
</span></span><span>Combine Like Terms </span>⇒ 3x−5=<span>(2x+x)+(8)
</span><span><span>3x</span>−5</span>=<span><span>3x</span>+<span>8
</span></span><span><span>3x</span>−5</span>=<span><span>3x</span>+<span>8
</span></span>Second thing we are now going to do is s<span>ubtract 3x from both sides<span> so:
</span></span><span><span><span>3x</span>−5</span>−<span>3x</span></span>=<span><span><span>3x</span>+8</span>−<span>3<span>x
</span></span></span><span>−5</span>=<span>8
</span>Final step is to add 5 to both sides:
−5+5=<span>8+5
</span>0=<span>13
</span>The answer to your question is "<span>There are no solutions"</span>
If you need the geometry and trigonometry I'll post those. Instead I found an answer at this link: http://jwilson.coe.uga.edu/EMAT6450/Class%20Projects/Scarpelli/Scarpelli_MathematicsBaseballActivity.....
The distance from home plate to the pitcher's mound is 60.5 feet and from home plate to second base is <span>127.28 feet.
Pitcher's Mound to 2nd base = </span><span>
<span>
<span>
66.78</span> </span>f</span>eet
Given those distances, we KNOW a 50 foot sprinkler will NOT reach home plate and second base from the pitcher's mound.
I didn't figure out the pitcher's mound to 1st or to 3rd, since the question is already answered.
