P = 2 × 4in + 2 × 1in = 8in + 2in = 10in
<h2><u>
P = 10 in</u></h2>
Answer:
FV(p)= PV*(1 + g)^t
Step-by-step explanation:
Giving the following information:
Number of insects (PV)= 1,500
Increase rate= 3 weekly
<u>First, we need to calculate the daily growth rate:</u>
Daily rate (g)= [3^(1/7)] - 1
Daily rate (g)= 0.16993
<u>Now, by using the following formula, we can determine the population p in any given day t:</u>
FV(p)= PV*(1 + g)^t
<u>For, example after 7 days:</u>
FV(p)= 1,500*(1.16993^7)
FV(p)= 4,500
<u>For example, after 10 days:</u>
FV(p)= 1,500*(1.16993^10)
FV(p)= 7,206
Answer:
Neither.
Step-by-step explanation:
I am not completely sure, so make sure to also let other answer this before you trust me lol. I really hope this helps!!
Answer:
Step-by-step explanation:
Answer:
yes
Step-by-step explanation:
The graph is of a function (one output for every input) that also passes the horizontal line test (one input for every output). Hence it is one-to-one.
For a <em>function</em>, the key for it being one-to-one is that it pass the horizontal line test.