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Scilla [17]
3 years ago
8

An equation was used to predict possible sales of phones for 6 months. The actual sales of phones are also listed.Actual sales 5

5 150 325 510 780 990Predicted sales 40 150 300 500 800 1,000The sum of the residuals is ______.Numerical Answers Expected!Answer for Blank 1:
Mathematics
1 answer:
Vikki [24]3 years ago
3 0

Answer:

20

Step-by-step explanation:

To calculate the sum of the residuals, subtract the predicted sales from the actual sales in the table below.

Actual sales 55 150 325 510 780 990

Predicted sales 40 150 300 500 800 1,000

This will show the change between them. Add each residual to find the sum.

55 - 40 = 15

150 - 150 = 0

325 - 300 = 25

510 - 500 = 10

780 - 800 = -20

990 - 1000 = -10

These add up to be 15 + 25+ 10 +-20 +-10  = 20

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Tomtit [17]

Answer:

I believe the value would be 9.

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Suppose the horses in a large stable have a mean weight of 975lbs, and a standard deviation of 52lbs. What is the probability th
Lubov Fominskaja [6]

Answer:

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 975, \sigma = 52, n = 31, s = \frac{52}{\sqrt{31}} = 9.34

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable?

pvalue of Z when X = 975 + 15 = 990 subtracted by the pvalue of Z when X = 975 - 15 = 960. So

X = 990

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{990 - 975}{9.34}

Z = 1.61

Z = 1.61 has a pvalue of 0.9463

X = 960

Z = \frac{X - \mu}{s}

Z = \frac{960 - 975}{9.34}

Z = -1.61

Z = -1.61 has a pvalue of 0.0537

0.9463 - 0.0537 = 0.8926

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

7 0
3 years ago
Es urjente
aleksklad [387]

Answer:

Espera espera espera.......

primer miembro es el independiente

incógnitas es la letra literal x b y c m

coeficiente es el resultado de la división

terminos independientes son aquellos los que no tienen cualquier letra 18 16 8

Step-by-step explanation:

espero que ayude

5 0
3 years ago
In analyzing statistical data, which do you think is more likely: a correlation coefficient of 0.9 or a correlation coefficient
alex41 [277]

Answer:

Is this middle school math I believe tha answer is 0.9

Step-by-step explanation:

I did it before pretyy sure thats what it is

4 0
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