<span>Area that needs to be painted=1600 sq.ft.
1 gallon of paint covers 250 sq.ft.
Total area for which paint needs to be bought=1600-250 sq.ft=1350 sq.ft. [Since, Mr. Arnold already has 1 gallon of paint]
Total paint that needs to be bought=1350/250=5.4 gallons
Alternatively,
Total paint required=(Area to be painted/Coverage of 1 gallon of paint)-1 [Since, Mr. Arnold already has 1 gallon of paint]
Total paint required= (1600/250)-1 gallons
=6.4-1 gallons=5.4 gallons of paint is required</span>
The common ratio between terms is 3, so the sequence has general
-th term
![a_n=3^{n-1}](https://tex.z-dn.net/?f=a_n%3D3%5E%7Bn-1%7D)
for
. The term exceeds 7000 when
![3^{n-1}>7000\implies n-1>\log_37000\implies n>1+\log_37000\approx9.06](https://tex.z-dn.net/?f=3%5E%7Bn-1%7D%3E7000%5Cimplies%20n-1%3E%5Clog_37000%5Cimplies%20n%3E1%2B%5Clog_37000%5Capprox9.06)
which means the first time
exceeds 7000 occurs when
. Indeed,
![a_{10}=3^{10-1}=19,683](https://tex.z-dn.net/?f=a_%7B10%7D%3D3%5E%7B10-1%7D%3D19%2C683)
while the previous term would have been
![a_9=3^{9-1}=6561](https://tex.z-dn.net/?f=a_9%3D3%5E%7B9-1%7D%3D6561)
Answer:
(0.88, 0,65)
Step-by-step explanation:
what do we have to do ? I assume we need to find the crossing point between the 2 lines.
when looking at the graphic, we can already rule out the first, third and fourth option.
none of the coordinates of that point is larger than 1 in any direction or smaller than 0.5.
so, just by looking at things I immediately "bet" on answer option 2 (0.88, 0.65).
but let's check.
y = -2x/5 + 1
y = 3x - 2
for the crossing point both functions must produce the same functional value.
=>
-2x/5 + 1 = 3x - 2
-2x/5 + 5/5 = 15x/5 - 10/5
-2x + 5 = 15x - 10
15 = 17x
x = 15/17 = 0.88...
y = 3×0.88... -2 = 0.65...
hurray, our original observation and "suspicion" is confirmed.
Answer:
130
Step-by-step explanation:
26/2 = 13
10 x 13 = 130
<span>x=<span><span><span>−b</span>±<span>√<span><span>b2</span>−<span><span>4a</span>c</span></span></span></span><span>2a</span></span></span><span>x=<span><span><span>−<span>(3)</span></span>±<span>√<span><span><span>(3)</span>2</span>−<span><span>4<span>(2)</span></span><span>(5)</span></span></span></span></span><span>2<span>(2)</span></span></span></span><span>x=<span><span><span><span>−3</span>±<span>√<span>−31</span></span></span>4</span>
</span></span>