What kind of shape will you see if you cut a cross section parallel to the base of a cylinder

Mathematics

2 answers:

Gwar [14]2 years ago

8 0

Answer:

Hexagons, Cross sections parallel to the base will be hexagons. It is also possible to take cross sections using planes that are neither parallel not perpendicular to the base

andrezito [222]2 years ago

8 0

Answer:

The cross-section parallel to the base is a hexagon congruent to the hexagonal bases. The cross-section perpendicular to the base is a rectangle. The cross-section parallel to the base is a pentagon similar to the pentagonal base. The solid is a cylinder.

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A zookeeper weighed an African elephant to be 9x10^3 pounds and an African lion to be 4x10^2 pounds. How many times greater is t

maria [59]

Answer: 22.5 . The weight of the elephant is "22.5 times greater" than the weight of the lion.
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Explanation:
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(weight of lion) * (x) = (eight of the elephant) ; Solve for "x" .
_____________________________________________________
→ Divide each side of the equation by "(weight of lion)" ;
to isolate "x" on one side of the equation ; and to solve for "x" ;
_________________________________________________________

→ (weight of lion)*(x) / (weight of lion) = (weight of the elephant) /
(weight of lion) ;
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→ x = (weight of the elephant) / (weight of lion) ;
__________________________________________________________
→ Plug in our "given values" ; and solve for "x" ;
__________________________________________________________
→ x = (9*10³) / (4*10²) = (9*10⁽³⁻²⁾) / 4 = (9*10¹) / 4 ;
__________________________________________________________
→ x = 90 /4 = 25/2 = 22.5 ; which is our answer.
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4 0

2 years ago

What is the measure of DE? 16 12 20 10

AnnyKZ [126]

set up a ratio to find the length:

15/12 = DE/16

cross multiply the 15 & 16:
15 * 16 = 240

divide that by 12 to get DE

240 / 12 = 20

DE = 20

8 0

2 years ago

The table shows the average annual cost of tuition at 4-year institutions from 2003 to 2010.

nata0808 [166]

Answer: 1) The best estimate for the average cost of tuition at a 4-year institution starting in 2020 =$ 31524.31

2) The slope of regression line b=937.97 represents the rate of change of average annual cost of tuition at 4-year institutions (y) from 2003 to 2010(x). Here,average annual cost of tuition at 4-year institutions is dependent on school years .

Step-by-step explanation:

1) For the given situation we need to find linear regression equation Y=a+bX for the given situation.

Let x be the number of years starting with 2003 to 2010.

i.e. n=8

and y be the average annual cost of tuition at 4-year institutions from 2003 to 2010.

With reference to table we get

$\sum x=36\\\sum y=150894\\\sum x^2=204\\\sum xy=718418$

By using above values find a and b for Y=a+bX, where b is the slope of regression line.

$a=\frac{(\sum y)(\sum x^2)-(\sum x)(\sum xy)}{n(\sum x^2)-(\sum x)^2}=\frac{150894(204)-(36)718418}{8(204)-(36)^2}=\frac{30782376-25863048}{1632-1296}=\frac{4919328}{336}\\\\=14640.85$

and

$b=\frac{n(\sum xy)-(\sum x)(\sum y)}{n(\sum x^2)-(\sum x)^2}=\frac{8(718418)-(36)150894}{8(204)-(36)^2}=\frac{5747344-5432184}{1632-1296}=\frac{315160}{336}\\\\=937.97$