25 = -16t^2 + 50t + 4
16t^2 - 50t + 21 = 0
16t^2 - 8t - 42t + 21 = 0
8t(2t - 1) - 21(2t - 1) = 0
(8t - 21)(2t - 1) = 0
8t - 21 = 0 or 2t - 1 = 0
t = 21/8 or t = 1/2
t = 2.625 or t = 0.5
Given:
i) 3, -5, -2, 1
ii) -1, -8, -7, -2
iii) -2, -4, 0, 2
To find:
increasing order of the given numbers.
Solution:
Increasing order: We need to start from the smallest number, then write larger number and end with the largest number.
We know that all negative numbers are less than the positive numbers and larger negative value is always the smaller one.
For example: -3 is less than -1.
i) We have,
3, -5, -2, 1
So, the increasing order of these number is -5, -3, -2, 1.
ii) We have,
-1, -8, -7, -2
So, the increasing order of these number is -8, -7, -2, -1.
iii) We have,
-2, -4, 0, 2
So, the increasing order of these number is -4, -2, 0, 2.
The applicable relation between force, mass, and acceleration is ...
... F = <em>m</em>a
Fill in the given values and solve for the mass.
... 0.75 N = <em>m</em>·3 m/s²
... (0.75 kg·m/s)/(3 m/s²) = <em>m</em> = 0.25 kg
The mass of the ball is 0.25 kg.
Answer:
18
Step-by-step explanation:
Volume is a product of cross-sectional area and height and relresented as V=Ah where V is volume, A is cross-sectional area and h is height.
For the square, since each has a thickness of 6mm then for 24 of them the height will be 24*6=144 mm
Since the volume and cross sectional area of the triangle should be the same, then the height should also be the same.
Since for the triangle each has a thickness of 8mm then the number requred to achieve a height of 144 mm will be 144/8=18 stacks
Answer: 
On a keyboard you would type sqrt(41)
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Work Shown:
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A slight alternative is to plot the point M(2,-5) to form right triangle LMN. The 90 degree angle is at point M.
The legs are of length LM = 4 and MN = 5, which are found by subtracting the x coordinates together and the y coordinates together (or you can count the spaces). From there, use the Pythagorean theorem to get the hypotenuse LN.
The distance formula is an altered version of the Pythagorean theorem.
