The possible outcomes could be:{123,124,125,134,135,145,234,235,245,345}
Their sums are as follows respectively:{6,7,8,8,9,10,9,10,11,12}=7
The odd sums are{7,9,11}=3
the probability of the sum being odd is 3/7
b.The number of outcomes are 10
the number of outcomes in which L is 4 are 3
So the probability of L being 4 is 3/10
Answer:
Step-by-step explanation:
Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter.To calculate combinations the below formula is used:
where represents the total number of items and represent the number of items being chosen at a time. The '!' represents factorial function which is the product of all integers equal to and less than the given integer. This can be calculated manually using the formula or by using the nCr function on a scientific calculator.
Thus, the number of ways to select 2 freshmen girls (2FG) and 3 freshmen boys (3FB) can be determined. The number of ways to select 5 students (5S) can be determined in the same way.
The probability of selecting 2 freshmen girls (2FG) and 3 freshmen boys (3FB) when selecting 5 students out of 30 is given as below:
Make it improper.
-4×25+4=96
96/25
make the bottom number 100
96× 4 25×4
384/100
simplify 3 and 84/100
3.84 is your answer
Answer:
the answer is 54.7
Step-by-step explanation:
82.6 - 27.9 = 54 7
Answer: 7 crayons
Step-by-step explanation:
To solve we first must find the total number of crayons available by adding up how many crayons are in each container.
56+12+96 = 160 crayons total
Next we take this number and divide it by 22 (the number of students in the class) to determine how many crayon each student gets
160 crayons/22 students = 7.272727 crayons per student
However, it's important to note that this number is not a whole number. We must then round down to the nearest whole number because students aren't given fractions of crayons.
7.272727 ==> 7 crayons per student