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Lilit [14]
3 years ago
7

CIRCLE THEOREM HELP:

Mathematics
1 answer:
raketka [301]3 years ago
5 0
I hope this helps you

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The area of a circle is 80.86cm2.<br> Find the length of the radius rounded to 2 DP.
weeeeeb [17]

Answer:

Solution given:

The area of a circle =80.86cm²

we have:

The area of a circle =πr²

substituting value of area of circle we get

80.86cm=3.14*r²

dividing both side by 3.14

80.86/3.14=3.14*r²/3.14

25.75=r²

doing square root on both side

\sqrt{25.75}=\sqrt{r²}

r=5.07cm

<u>The</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>radius</u><u> </u><u>is</u><u> </u><u>5</u><u>.</u><u>0</u><u>7</u><u>cm</u>

5 0
2 years ago
Which of the following could be the ratio between the lengths of the two legs
skad [1K]

9514 1404 393

Answer:

  B, E

Step-by-step explanation:

The ratios of side lengths in a 30-60-90 triangle are ...

  1 : √3 : 2

The two legs are the shorter sides, so any ratio that reduces to 1 : √3 is an appropriate choice:

  B.  1 : √3

  E.  2√3 : 6

3 0
3 years ago
The double dot plot shows the number of points scored by Sam and Daniel in 15 games. What is the difference between their median
just olya [345]

Answer:

4.9

Step-by-step explanation:

7 0
2 years ago
What is the measure of angle DBC
MAXImum [283]
The angle measure of DBC is 45
3 0
3 years ago
If you are dealt 4 cards from a shuffled deck of 52 cards, find the probability of getting two queens and two kings.
Bingel [31]

<u>Given</u>:

If you are dealt 4 cards from a shuffled deck of 52 cards.

We need to determine the probability of getting two queens and two kings.

<u>Probability of getting two queens and two kings:</u>

The number of ways of getting two queens is 4C_2

The number of ways of getting two kings is 4C_2

Total number of cases is 52C_4

The probability of getting two queens and two kings is given by

\text {probability}=\frac{\text {No.of fanourable cases}}{\text {Total no.of cases}}

Substituting the values, we get;

probability=\frac{4C_2 \cdot 4C_2}{52C_4}

Simplifying, we get;

probability=\frac{6 (6)}{270725}

probability=\frac{36}{270725}

probability=0.000133

Thus, the probability of getting two queens and two kings is 0.000133

7 0
3 years ago
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