It would be C. -4 < x < 7
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Two numbers make up the factors of 1000. <span>In order that neither of the numbers be divisible by ten, each must contain powers of only one of the prime factors of 10, namely, 2 OR 5.</span>
So let's see what we can cook up. The obvious answer is
1000 = 10 * 10 * 10
1000 = 2*5 * 2*5 * 2*5
1000 = 2^3 * 5^3
1000 = 8 * 125 Are there any others?
I don't think so. The answer then comes to 8 + 125 = 133
You might argue that -8 * - 125 would also work. But the question says natural numbers not integers.
so maybe 6 plus 3 which equals 9. Then add 8 at the end
The LCM is
600. 900
1200. 1800
1800. 2700
2400. (3600)
3000. 4500
(3600.). 5400
4200. 6300
