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3 years ago

Any idea help me ASAP:)

Mathematics

1 answer:

Arada [10]3 years ago

5 0

Answer:

The x-intercept is (18/5, 0).

The y-intercept is (0,-2).

Step-by-step explanation:

To find the x-intercept, sub y for 0.

-5x + 9y = -18

-5x + 9(0) = -18

Simplify and isolate x.

-5x = -18 <= Divide both sides by -5

x = 18/5

Since we substituted y for 0, y=0.

(18/5, 0)

To find the y-intercept, sub x for 0.

-5x + 9y = -18

-5(0) + 9y = -18

Simplify and isolate y.

9y = -18 <= Divide both sides by 9

y = -2

Since we substituted x for 0, x=0.

(0,-2)

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4 years ago

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3 years ago

The probability of winning on an arcade game is 0. 659. if you play the arcade game 30 times, what is the probability of winning

mrs_skeptik [129]

The probability of winning exactly 21 times is:-0.32

Given,

The probability of winning on an arcade game, p = 0.659

Number of times you play arcade game, n = 30

By assuming this as a normal distribution, we get

Mean=μ=30×0.659 =19.77

Standard deviation, σ = $\sqrt{np(1-p)}$

= $\sqrt{30(0.659)(1-0.659)}$

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Let X be a binomial variable

Then, the z score for x = 21 will be:

z = (x - μ) / σ = $\frac{21-19.77}{2.60}$

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Now, the probability of winning exactly 21 times

P (x ≥ z) = P (21 ≥ 0.47) = 0.32

Hence the probability of winning exactly 21 times is 0.32

Learn more about probability here:-brainly.com/question/13067945

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2 years ago

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Ymorist [56]

Answer:

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3 years ago