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Vanyuwa [196]
3 years ago
10

Need some help working these out

Mathematics
1 answer:
s2008m [1.1K]3 years ago
3 0

Answers:

  • Problem 1)  40 degrees
  • Problem 2) 84 degrees
  • Problem 3) 110 degrees

===============================================

Explanation:

For these questions, we'll use the inscribed angle theorem. This says that the inscribed angle is half the measure of the arc it cuts off. An inscribed angle is one where the vertex of the angle lies on the circle, as problem 1 indicates.

For problem 1, the arc measure is 80 degrees, so half that is 40. This is the measure of the unknown inscribed angle.

Problem 2 will have us work in reverse to double the inscribed angle 42 to get 84.

-------------------

For problem 3, we need to determine angle DEP. But first, we'll need Thales Theorem which is a special case of the inscribed angle theorem. This theorem states that if you have a semicircle, then any inscribed angle will always be 90 degrees. This is a handy way to form 90 degree angles if all you have is a compass and straightedge.

This all means that angle DEF is a right angle and 90 degrees.

So,

(angle DEP) + (angle PEF) = angle DEF

(angle DEP) + (35) = 90

angle DEP = 90 - 35

angle DEP = 55

The inscribed angle DEP cuts off the arc we want to find. Using the inscribed angle theorem, we double 55 to get 110 which is the measure of minor arc FD.

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Help!! help!! help!! help!! help!! help!! help!! help!! help!!
oksian1 [2.3K]

Answer:

<em>(8.21, -20.79)</em>

Step-by-step explanation:

Given the simultaneous equation;

\frac{a}{b} - \frac{b}{2} = 10\\a - b = 29

From 2;

a = 29 + b ....3

Substitute 3 into 1;

\frac{29+b}{b} - \frac{b}{2}  = 10\\\frac{2(29+b)-b^2}{2b} = 10\\\frac{58+2b-b^2}{2b} = 10\\58+2b-b^2 = 20b\\b^2-2b-58 = -20b\\b^2-2b+20b -58 = 0\\b^2+18b-58 = 0\\

Factorize

b = -18±√18²-4(-58)/2

b = -18±√324+232/2

b = -18±√556/2

b = -18±23.58/2

b = -18-23.58/2 and -18+23.58/2

b = -41.58/2 and 5.58/2

b = -20.79 and 2.79

Since a = 29 + b

when b = -20.79

a = 29 - 20.79

a = 8.21

<em>Hence the solution to the system of equation is (8.21, -20.79)</em>

7 0
2 years ago
The difference of two rational numbers is always negative true of false
Vlada [557]

Comparing two rational numbers

Use fraction form:

 

Make the denominators the same and compare the numerators. The number with the smaller numerator is smaller. For example, to compare a/b and c/d, we rewrite

 

a/b=a*d/b*d

  = ad/bd and c/d = c*b/d*b=bc/bd

 

Now just compare the numerators : "ad" and "bc"

 

Multiplying and Dividing Rational Numbers 

 

Multiplying and dividing rational numbers in decimal form is the same as multiplying and dividing integers. The decimal place of the product is the same of all decimals of all multiplied numbers. For example, 3.12*2.4.

 

Solution => 3.12*2.4=7.488

 

When multiplying or dividing rational numbers in fractional form, you multiply the numerators (N*N) and then multiply the denominators (D*D).

 

When dividing rational numbers in fractional form, first take the reciprocal of the divisor, and then multiply the numerators and the denominators.

 

Example => 5/9 divided by 2/7 .

 

Solution => 5/9 * 7/2 =  35/18

 

 

Adding Rational numbers

 

Adding and Subtracting rational numbers in decimal form is the same as adding and subtracting integers.

 

Example => -3.54+2.79=-0.75

 

When adding or subtracting rational numbers in fractional form, first make the denominator equal, and then add or subtract the numerators.  

The difference can be negative or positive. 

7 0
3 years ago
) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle
Fynjy0 [20]

The surface (call it S) is a triangle with vertices at the points

x=0,y=0\implies z=2\implies(0,0,2)

x=0,y=2\implies z=-2\implies(0,2,-2)

x=2,y=0\implies z=-8\implies(2,0,-8)

Parameterize S by

\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)

with 0\le u\le1 and 0\le v\le1. Take the normal vector to S to be

\vec s_v\times\vec s_u=(20v,8v,4v)

Then the flux of \vec F across S is

\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv

=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}

8 0
3 years ago
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elixir [45]

Answer:

this is simple... 1 3/4

Step-by-step explanation:

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y = mx+b

y = f(×)

b = y-intercept

m = slope (slope = rise/run, rise over run)

rise is y-axis
run is x-axis

The y-intercept is (0,-2)
So now we know that one of the answers must have -2 in it

b = -2

m= rise/run = -2/3

The answer is:

f(x) = - \frac{2 }{3 } x - 2
5 0
2 years ago
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