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oksian1 [2.3K]
3 years ago
7

7. What are the "coefficients" in this problem? 8 + 4ab - 5b

Mathematics
2 answers:
katovenus [111]3 years ago
6 0

Answer:

4 and -5

Step-by-step explanation:

Iteru [2.4K]3 years ago
6 0

Answer:

4 and -5

Step-by-step explanation:

Coefficients are numbers that are multiplied by a variable.

The term <em>4ab</em> has 4 as the coefficient and <em>a </em>and <em>b</em> as the variables.

The term <em>-5b</em> has -5 as the coefficient and <em>b </em>as the variable.

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∆ABC is reflected about the line y = -x to give ∆A'B'C' with vertices A'(-1, 1), B'(-2, -1), C(-1, 0). What are the vertices of
blsea [12.9K]
Hi there!
Reflections across the line y = -x always go by the rule (-y, -x). We can use this rule to get our answer here. We are given the aftermath of the reflection coordinates, which are <span>A'(-1, 1), B'(-2, -1), and C'(-1, 0). All we have to do now is switch up the coordinate values and multiply them by -1. Here is the work - 
A'(-1, 1) => (1, -1) => x -1 => A(-1, 1)
B'(-2, -1) => (-1, -2) => x -1 => B(1, 2)
C'(-1, 0) => (0, -1) => x -1 => C(0, 1)
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6 0
4 years ago
Read 2 more answers
Solve for w. -3( -7w+4) - 7w=2(w-3)-3
ch4aika [34]

Answer:

Im not sure how you need the answer so i put it in different forms for you

w=1/4

w=0.25

w=2^-2

Step-by-step explanation:

They are all the same thing

8 0
3 years ago
Round 2.15 to nearest tenth
guapka [62]
2.2 maybe? I would check with someone
4 0
3 years ago
Find the surface area of a cone with a radius of 7 cm and a height of 27 cm
Nataly_w [17]
Your answer: A≈767.33cm²
7 0
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Find the area of an equilateral triangle (regular 3-gon) with the given measurement.
kow [346]

If the perimeter is 9 inches, each side is 3 inches.

The height of an equilateral triangle splits the triangle in two right sub-triangles: for example, consider a triangle ABC and the height AH starting from A, perpendicular to BC.

The triangle AHC is a right triangle, whose legs are AH and HC, and whose hypotenuse is AC.

AH is half the side, and AC is a side. So, we can use the Pythagorean theorem to find the height:

AH = \sqrt{AC^2-AH^2}=\sqrt{l^2-\dfrac{l^2}{4}}=\dfrac{\sqrt{3}l}{2}

So, the area is

\dfrac{AH\cdot HC}{2} = \dfrac{l\cdot\frac{\sqrt{3}l}{2}}{2} = \dfrac{l^2\sqrt{3}}{4} = \dfrac{9\sqrt{3}}{4}

6 0
4 years ago
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