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Brrunno [24]
3 years ago
9

Lily is making costumes. She buys

Mathematics
1 answer:
jek_recluse [69]3 years ago
5 0

9514 1404 393

Answer:

  terms: 5m, 7p

Step-by-step explanation:

The terms of the expression are the products that are separated by addition or subtraction: 5m and 7p.

The term 5m represents the cost of 5 yards of fabric at m dollars per yard.

The term 7p represents the cost of 7 yards of fabric at p dollars per yard.

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Xy-2x=3y. Solve for x
Llana [10]

xy - 2x = 3y \\ x(y - 2) = 3y \\ x =  \frac{3y}{y - 2}
5 0
4 years ago
A carpenter is building a rectangular room with a fixed perimeter of 300 ft. what dimensions would yield the maximum​ area?
Inessa05 [86]

Perimeter = 2(Length) + 2(Width)

300 = 2L + 2W → 150 = L + W → 150 - L = W

Area = Length · Width

A_{max} = L(150 - L) → A_{max} = 150L - L²

There are 2 different methods for solving (depending on which math course you are taking).

<u>Calculus</u>: find the derivative, set it equal to zero, and solve for L.

A_{max} = 150L - L² → 0 = 150 - 2L → 2L = 150 → L = 75

<u>Algebra</u>: find the vertex.

A_{max} = - L² + 150L → L = -b/2a → L = -150/2(-1) → L = 75

Once you solve for L, plug it into the Perimeter equation to solve for W:

150 - L = W → 150 - 75 = W → W = 75

Answer: 75ft x 75ft


3 0
4 years ago
A survey was done where boys and girls were asked if they would prefer to play inside or outside. The results of the survey are
Andrei [34K]
Add the number of boys that prefer to play inside and the number that prefer to play outside and then divide the ones that prefer inside by the total. The answer is 43.4 percent
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4 years ago
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88............................

3 0
4 years ago
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Determine whether the improper integral converges or diverges, and find the value of each that converges.
Marina86 [1]

Answer:

Divergent.

Step-by-step explanation:

We have been given an integral \int\limits^\infty _1 {\frac{1}{x^{0.999}} \, dx. We are asked to determine whether the given integral diverges or converges.

\int _1^{\infty }\:\:\:\frac{1}{x^{0.999}}\:\:\:dx

\int _1^{\infty }\:\:\:\frac{1}{x^{0.999}}\:\:\:dx=\int _1^{\infty }\:\:\:x^{-0.999}\:\:\:dx

\int _1^{\infty }\:\:\:x^{-0.999}\:\:\:dx=\frac{x^{-0.999+1}}{-0.999+1}

\int _1^{\infty }\:\:\:x^{-0.999}\:\:\:dx=\frac{x^{0.001}}{0.001}

\int _1^{\infty }\:\:\:x^{-0.999}\:\:\:dx=1000x^{0.001}

Let us compute the boundaries.

1000(\infty)^{0.001}=\infty

1000(1)^{0.001}=1000

Since \infty-1000 is not a finite number, therefore, the given integral diverges.

4 0
3 years ago
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