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ohaa [14]
4 years ago
15

Consider the isosceles triangle with verticles a(-1,1) b(3,1) c(1,6)

Mathematics
1 answer:
Dima020 [189]4 years ago
8 0
What is the question? Do they want us to find a’,b’, and c’??
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I think 5/60.......

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3 years ago
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Naddika [18.5K]
   
\displaystyle\\
15(2a - 2) = 5(a^2 -1) \\  \\ 
30a - 30 = 5a^2-5\\\\
-5a^2 + 30a -30 + 5 =0\\\\
-5a^2 + 30a -25 =0 ~~~~~\Big| \times (-1) \\\\
5a^2 - 30a +25 = 0~~~~~\Big| : 5 \\\\
a^2 - 6a +5 = 0 \\  \\ 
a_{12}= \frac{-b\pm \sqrt{b^2-4ac}}{2a}= \frac{6\pm \sqrt{36-20}}{2}= \frac{6\pm \sqrt{16}}{2}=\frac{6\pm 4}{2}= \boxed{3\pm 2} \\  \\ 
a_1 = 3+ 2 = \boxed{5}\\\\
a_2 = 3-2 = \boxed{1}



8 0
3 years ago
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Amanda [17]

Answer:

2/3 of n +5>12

Step-by-step explanation:

6 0
2 years ago
How would I do this
xz_007 [3.2K]
When,
correct is 0 then p is 0/20.
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correct is 3 p is 3/20.
correct is 4 p is 4/20 that is 1/5
correct is 5 p is 5/20 that is 1/4

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3 years ago
SOMEONE HELP PLEASE! i’m stuck!! HELP IF YOU WANT THE BRAINIEST!!
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3 years ago
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